A x = 0
using the law of exponents = 1
for (6² )^ x = 1 then x = 0
B note that = 1 ⇒ x = 1
2 → 2^8 × 3^(-5) × 1^(-2) × 3^(-8) × 2^(-12) × 2^(28)
= 2^(8 -12 + 28) × 1 × 3^(- 5 - 8)
= 2^24 × 3^(- 13) = 2^(24)/3^(13) = 10.523 ( 3 dec. places)
Step-by-step explanation:
There are four possible values of X: 0 rats show side effects, 1 rat shows side effects, 2 rats show side effects, or all 3 rats show side effects.
Probability X = 0:
P = (1 − 0.5) (1 − 0.4) (1 − 0.3)
P = 0.21
Probability X = 1:
P = (0.5) (1 − 0.4) (1 − 0.3) + (1 − 0.5) (0.4) (1 − 0.3) + (1 − 0.5) (1 − 0.4) (0.3)
P = 0.44
Probability X = 2:
P = (0.5) (0.4) (1 − 0.3) + (0.5) (1 − 0.4) (0.3) + (1 − 0.5) (0.4) (0.3)
P = 0.29
Probability X = 3:
P = (0.5) (0.4) (0.3)
P = 0.06
Answer:
-1
Step-by-step explanation:
2x² - 5x + 7 is subtracted <em>from </em>x² + 2x - 11, so
(x² + 2x - 11) - (2x² - 5x + 7)
x² + 2x - 11 - 2x² + 5x -7 (Distribute the negative)
-x² + 7x - 18 (Combine like terms)
The leading coefficient is the coefficient of the first term, so it is -1.
Because of the fact that the amberjack is essentially three snappers, it can be shown as 3s
since one snapper is one s, and the amberjack is 3s, we can combine like terms
s+3s = 4s
because altogether, the fish weigh 44 pounds, 4s would equal 44 (shown as 4s = 44), from there, simply divide by 4 on both sides to get the weight of a snapper;
s = 11
Small bonus (finding an amberjack)
Since an amberjack is equal to three snappers, and a snapper is 11 pounds, an amberjack would be 33 pounds.
Answer:
Yes, Hamdan is correct.
Step-by-step explanation:
Let the two fractions are q/r and s/r.
Here, the denominator is same for both the fractions.
So, as we add them, add the numerators and the denominators remains same.
For example
So, Hamdan is correct.