The volume would be V = (side of base)^2 * (height). The height would be 3. To see this, make yourself a model if need be. Assuming that the dimensions of the "square piece of cardboard" are x by x, then the length (or the width) of a side of the square bottom would be x-3-3, or x - 6.
So: V = (x-6)^2*3 = (area of base)*(depth of box)
= 3(x-6)^2 (answer)
Answer:
D
Step-by-step explanation:
The answer is B hope that helps
Answer:
D) Neither X nor Y can be well approximated by a normal random variable.
Step-by-step explanation:
X = number of males (out of the 20) who are colorblind.
Y = number of females (out of the 40) who are colorblind.
Z = total number of colorblind individuals in the sample (males and females together).
The condition to use the normal approximation is that np > 5 and nq > 5
For X:
n = 20, p = 8% = 0.08,
q = 1 - 0.08 = 0.92
np = 20 * 0.08
np = 1.6 ( np < 5)
np = 20 * 0.92
np = 18.4 ( nq > 5)
For Y:
n = 40, p = 1% = 0.01,
q = 1 - 0.01 = 0.99
np = 40 * 0.01
np = 0.4 ( np < 5)
np = 40 * 0.99
np = 39.6 ( nq > 5)
For both X and Y, np < 5 and nq > 5. Since both np and nq are not greater than 5, both samples cannot be approximated by a normal distribution.
2.1 or 2. Hopefully this is right.
