Best answer is: Owners manual based on driving habits
Explanation:
If you are one of the many people who let a windshield reminder sticker govern when they get an oil change, here's our advice to you: Drop that habit. Instead, follow the automaker's recommended service intervals. In many modern cars, your best bet is to rely on the vehicle's oil life monitoring system to let you know when it's time for a change.
Answer:
b. adds to Iterator the ability to move backwards in the collection
Explanation:
In Java programming, the ListIterator interface adds to Iterator the ability to be bidirectional i.e move backwards and forward in the collection and it is a sub-interface of the Iterator interface.
The ListIterator interface makes it possible to modify any list during iteration and determine its position in the list.
Answer:
Python is the correct answer.
Explanation:
Python Programming Language is might be good for those programmers who are beginners because the following Language is quite easy and simple to learn. When any programmer using Python Language for the programming then, they easily write their program because of its simplicity, it is easy and quick for learning language. This language creates program easy and short.
The code that carried out the functions indicated above is stated below. It is not be noted that the code is written in C#
<h3>
What is C#</h3>
C# is a type-safe, object-oriented programming language. It is pronounced "see sharp"
<h3>
What is the code for the above task?</h3>
Using System;
public class HoursAndMinutes
{
public static void Main()
{
// declaring minutes variable and assigning 197 as given in question
int minutes = 197;
// outputing the total minutes , hours
Console.WriteLine("{0} minutes is {1} hours and {2} minutes.", minutes, minutes/60, minutes%60);
}
}
// OUT
Learn more about C#:
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Answer:
#include <string>
#include <iostream>
using namespace std;
int main() {
string userInput;
getline(cin, userInput);
// Here, an integer variable is declared to find that the user entered string consist of word darn or not
int isPresent = userInput.find("darn");
if (isPresent > 0){
cout << "Censored" << endl;
// Solution starts here
else
{
cout << userInput << endl;
}
// End of solution
return 0;
}
// End of Program
The proposed solution added an else statement to the code
This will enable the program to print the userInput if userInput doesn't contain the word darn
