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Anestetic [448]
3 years ago
7

Which best explains whether a triangle with side lengths 5 cm, 13 cm, and 12 cm, is a right triangle?

Mathematics
2 answers:
Llana [10]3 years ago
7 0
The Pythagorean Proposition can help you explain this:
{a}^{2}  =  {b}^{2}  +  {c}^{2}  \\ {13}^{2}  =  {5}^{2}  +  {12}^{2}  \\ 169 = 25 + 144
Furkat [3]3 years ago
3 0

Answer:

Let first side= 5 cm

second side= 12 cm

third side = 13 cm

To prove this triangle to be right angle triangle, we need to prove Pythagoras Theorem

5^{2}=25

12^{2}=144

13^{2}=169

169= 25+144

169=169

According to Pythagoras theorem ,

p^{2}+b^{2}=h^{2}

since, it follows Pythagoras theorem,

Hence, it is a Right angle Triangle

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A clothing company sells slacks that are either blue or gray and pleated or non-pleated. Last month, the company sold 5 times as
abruzzese [7]

Answer:

88

Step-by-step explanation:

5GP= BP

2BNP= GNP

BP+BNP=333

GP+GNP=225

BNP= 333-BP

BNP= 333-5GP

GP= 225-GNP

GP= 225-2BNP

BNP=333-5(225-2BNP)

BNP=333-1125+10BNP

-9BNP=-792

BNP=88

Hope it helps :)

Mark Brainliest if possible.

7 0
4 years ago
Read 2 more answers
How many solutions does the equation 6y − 3y − 7 = −2 + 3 have?
Ludmilka [50]
The only solution to this equation is 8/3, therefore the answer is C.
4 0
3 years ago
2 of 2<br> X= 1<br> True<br> False
stepan [7]

Answer:

of means to multiple so it would equal 4 so the answer is false

4 0
3 years ago
Write an inequality for the given graph.
Aliun [14]
Y=MX+B

M = slope

B = y intercept (number that intersects with the line in the y axis)

y=-3/4x+2

It starts on the y intercept (2) then we travel to the next point (4 on the x axis)

So we travel 3 spaces down (-3) landing on the origin (0,0) then four spaces to the right (4). Getting the slope of -3/4 (rise over run)

Then just plug in these into the equation

y = -3/4 + 2
5 0
3 years ago
A square pyramid is shown: 0.4 feet , 0.4 feet , 5 feet What is the surface area of the pyramid?
Vlad [161]
A square pyramid is called like so because its base is a square.

notice this one, its base is a 0.4x0.4 square, and the triangular faces have a base of 0.4 and an altitude or height of 5.

so we can simply get the area of the base and all four triangular faces and sum them up, and that's the surface area of the pyramid.

\bf \stackrel{\textit{squarish base}}{(0.4\cdot 0.4)}~~+~~\stackrel{\textit{4 triangles}}{4\left[\cfrac{1}{2}(0.4)(5)  \right]}\implies 0.16~~+~~4\implies 4.16
5 0
3 years ago
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