Hi there!
We are given the equation w² + 7w + 12 = 0, and we are told to solve it. Well, we can first take all the factors of 12 -
1 12
2 6
3 4
Now, take the sum of each factor pair -
1, 12 = 13
2, 6 = 8
3, 4 = 7
Find which factor pair adds up to 7, and we can see that 3 and 4 add up to seven, while also having a product of 12. Therefore, since the whole equation has addition signs, we can factor the equation w² + 7w + 12 into (w + 3)(w + 4) = 0. Next, using the Zero Product Property, we can set each term to zero.
w + 3 = 0
w = -3
w + 4 = 0
w = -4
Therefore, the solution to the equation w² + 7w + 12 = 0 is w = -3, -4. Hope this helped and have a great day!
9514 1404 393
Answer:
both are (-∞, ∞)
Step-by-step explanation:
The domain and range of any odd-degree polynomial are both "all real numbers." They go from -infinity to +infinity.
Your polynomial is of degree 3, so is of odd degree. The arrows on the ends of the curve indicate it extends to infinity in that direction.
y → +∞ for x → +∞
y → -∞ for x → -∞
3/4 - 2/4 = 1/4....Lee reads 1/4 of an hr more (or 15 minutes more) in the morning then in the afternoon.
1, 3 not really any explanation