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vampirchik [111]

3 years ago

5

Iliana's math grade increased from 65 to 86. Fiona's math grade increased from 70 to 80. What is the difference, rounded to the

nearest whole number, between the approximate percent increases? What percent is it

1 answer:

NikAS [45]3 years ago

8 0

Answer:

18%

Step-by-step explanation:

Iliana's math grade increased from 65 to 86.

So, the percentage increase in the her math grade will be $\frac{(86-65) \times 100}{65} = 32.31$ % (Approximate)

Now, Fiona's math grade increased from 70 to 80.

Hence, the percentage increase in her math grade will be $\frac{(80-70)\times 100}{70} =14.28$ % (Approximate)

So, the difference rounded to the nearest whole number between the approximate percent increases in math grades will be

(32.31 - 14.28) ≈ 18%

So, it is eighteen percent. (Answer)

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Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

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Free_Kalibri [48]

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so $990 will be the discount.

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Answer

Find the volume of the coin is cubic millimeters.

To prove

Formula

$Volume\ of\ cylinder\ = \pi r^{2} h$

Where r is the radius and h is the height .

As given

The $1 coin depicts Sacagawea and her infant son.

The diameter of the coin is 26.5 mm, and the thickness is 2.00 mm.

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3 years ago

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