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dedylja [7]
3 years ago
9

I need help on this problem. Solve for c

Mathematics
2 answers:
DanielleElmas [232]3 years ago
8 0
First you need to multiply each side by 2

X - C. X - C = d * 2
-------- = d --->
2
Then add X from each side

C = d * 2 + X
Katen [24]3 years ago
3 0
Remember, you can do anything to an equation as long as you do it to both sides


\frac{x-c}{2}=d
multiply both sides by 2
x-c=2d
minus x from both sides
-c=2d-x
multiplly both sides by -1
c=x-2d
You might be interested in
A rectangle has a length that is 5 inches greater than its width, and its area is 104 square inches. The equation (x + 5)x = 104
mina [271]
1. Regroup terms
x(x+5)=104

2. Expand
x^2+5x=104

3. Move all terms to one side
x^2+5x-104=0

4. Factor x^2+5x-104
(x-8)(x+13)=0

5. Solve for x
x=8 or x=-13
Since x<0 is not possible in this case, x=8

6. Finding the dimensions
We know that one side has to be x+5, and now that we know x:
8+5=13
13*8=104

The dimensions are 13 and 8, have a nice day :D
8 0
3 years ago
Read 2 more answers
9. What is the solution to this equation? 2x + 10 = 28 help​
abruzzese [7]

Answer: x=9

Step-by-step explanation:

2x+10=28

2x=18

x=9

5 0
3 years ago
Read 2 more answers
Please solve this, will rate 5 stars and mark as STAR!​
Nina [5.8K]

Answer:

\boxed{5 \cdot \sqrt{2}  \cdot \sqrt[6]{5} }

Step-by-step explanation:

\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}

\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}

\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }

250=2 \cdot 5^3

\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5  \sqrt[3]{2}

Once

\sqrt[6]{2}  \cdot \sqrt[6]{5} = \sqrt[6]{10}

We have

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5}

We can proceed considering the common base of exponentials

\sqrt[3]{2}  \cdot \sqrt[6]{2}  =  2^{\frac{1}{3}} \cdot  2^{\frac{1}{6} }  = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}

Therefore,

5  \sqrt[3]{2} \cdot \sqrt[6]{2}  \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2}  \cdot \sqrt[6]{5}

7 0
3 years ago
Type the integer that makes the following subtraction sentence true:<br><br> – 7 = -3
Shkiper50 [21]
4 because -7 plus 4 = 3

4 0
3 years ago
-14^2-8+3-6x^2+7x-11
denis-greek [22]
The answer is <span><span>−<span>6<span>x2</span></span></span>+<span>7x</span></span>−<span>212</span>
5 0
3 years ago
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