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mars1129 [50]
3 years ago
7

Is -9 a solution to 19>8u+3

Mathematics
2 answers:
iVinArrow [24]3 years ago
4 0
8u+3<19  subtract 3 from both sides

8u<16  divide both sides by 8

u<2 so

-9 is in the solution set u=(-oo, 2)
Irina18 [472]3 years ago
3 0
1 Subtract 3 from both sides

<span><span>19−3>8u</span>
2 Simplify 19-3 to <span>16

</span>16>8<span>u
</span>
3 Divide both sides by <span>8

16/8 > u

</span>4 Simplify 16/8 to 2

2 > u

5 Switch sides

u < 2

I hope this helps. :)


</span>
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Is the solution of this equation extraneous?
UkoKoshka [18]

Answer:

x = - 3 is extraneous

Step-by-step explanation:

Given

\sqrt{x+7} - 1 = x  ( add 1 to both sides )

\sqrt{x+7} = x + 1 ( square both sides )

x + 7 = (x + 1)² ← distribute right side

x + 7 = x² + 2x + 1 ( subtract x + 7 from both sides )

0 = x² + x - 6 ← in standard form

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Equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x - 2 = 0 ⇒ x = 2

As a check

Substitute these values into the equation and if both sides are equal then they are the solutions.

x = - 3 : \sqrt{-3+7} - 1 = \sqrt{4} - 1 = 2 - 1 = 1 ≠ - 3

x = 2 : \sqrt{2+7} - 1  = \sqrt{9} - 1 = 3 - 1 = 2

x = 2 is a solution and x = - 3 is extraneous

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3 years ago
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ValentinkaMS [17]
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Marina86 [1]
X=26/3
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