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Answer:
(a) 0.29412 .
(b) No, the events selecting company A and incurring in cost overruns are not independent.
Step-by-step explanation:
We are given that a certain federal agency employs three consulting firms (A, B and C) with probabilities 0.4, 0.35 and 0.25 respectively i.e.;
P(A) = 0.4 P(B) = 0.35 P(C) = 0.25
Also, From past experience it is known that the probability of cost overruns for the firms are 0.05, 0.03, and 0.15, respectively which means;
Let CO = Event of cost overruns
P(CO/A) = 0.05 - It means probability of cost overruns given the consulting firm involved was A.
Similarly, P(CO/B) = 0.03 P(CO/C) = 0.15
(a) Probability that the consulting firm involved is company A given a cost overrun is experienced by the company is given by, P(A/CO);
We will use Bayes' theorem here calculating the above probability ;
P(A/CO) =
= = 0.29412 .
(b) No, the events selecting company A and incurring in cost overruns are not independent because the cost overruns happens only when the consulting firm is involved and also the cost overruns will differ as we move towards another consulting firm so the chances of cost overruns will depend on the fact that which consulting firm has been involved.
With the provided vertices and the focus point, the hyperbola will look like the one in the picture below.
notice the "c" distance from the center to the focus point.
since it's a vertical hyperbola, the positive fraction will be the one with the "y" in it, its center is clearly half-way between the vertices at -5, 5.
its major axis or traverse axis goes from -2 up to 12, so is 14 units long, therefore the "a" component is half that, or 7.
![\bf \begin{cases} h=-5\\ k=5\\ a=7\\ c=25 \end{cases}\implies \cfrac{(y-5)^2}{7^2}-\cfrac{[x-(-5)]^2}{b}=1 \\\\\\ \cfrac{(y-5)^2}{7^2}-\cfrac{(x+5)^2}{b}=1\\\\ -------------------------------\\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b\implies \sqrt{25^2-7^2}=b \\\\\\ \sqrt{625-49}=b\implies \sqrt{576}=b\implies 24=b\\\\ -------------------------------\\\\ \cfrac{(y-5)^2}{7^2}-\cfrac{(x+5)^2}{24^2}=1\implies \cfrac{(y-5)^2}{49}-\cfrac{(x+5)^2}{576}=1](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0Ah%3D-5%5C%5C%0Ak%3D5%5C%5C%0Aa%3D7%5C%5C%0Ac%3D25%0A%5Cend%7Bcases%7D%5Cimplies%20%5Ccfrac%7B%28y-5%29%5E2%7D%7B7%5E2%7D-%5Ccfrac%7B%5Bx-%28-5%29%5D%5E2%7D%7Bb%7D%3D1%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B%28y-5%29%5E2%7D%7B7%5E2%7D-%5Ccfrac%7B%28x%2B5%29%5E2%7D%7Bb%7D%3D1%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0Ac%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20%5Csqrt%7Bc%5E2-a%5E2%7D%3Db%5Cimplies%20%5Csqrt%7B25%5E2-7%5E2%7D%3Db%0A%5C%5C%5C%5C%5C%5C%0A%5Csqrt%7B625-49%7D%3Db%5Cimplies%20%5Csqrt%7B576%7D%3Db%5Cimplies%2024%3Db%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%5Ccfrac%7B%28y-5%29%5E2%7D%7B7%5E2%7D-%5Ccfrac%7B%28x%2B5%29%5E2%7D%7B24%5E2%7D%3D1%5Cimplies%20%5Ccfrac%7B%28y-5%29%5E2%7D%7B49%7D-%5Ccfrac%7B%28x%2B5%29%5E2%7D%7B576%7D%3D1)
notice the "c" distance from the center to the focus point.
since it's a vertical hyperbola, the positive fraction will be the one with the "y" in it, its center is clearly half-way between the vertices at -5, 5.
its major axis or traverse axis goes from -2 up to 12, so is 14 units long, therefore the "a" component is half that, or 7.