The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
64x^127
Step-by-step explanation:
caculate it with all the numb
Answer:
B.
Step-by-step explanation:
because y is a rotation that rotates up and down like a ramp!
10%
= 10/100
= 1/10
10% in its simplest form is 1/10~
Answer:
Length = 3 cm
Width = 1 cm
Step-by-step explanation:
Let the length of rectangle be l and width of rectangle be w.
According to problem,
l = 3w {Length of rectangle is equal to triple the width}
And Perimeter,P = 8 cm
Since, P = 2 ( l + w )
or 8 = 2( l + w)
Plug l =3w in the above perimeter equation.
We get:
8 = 2( 3w + w)
8 = 2(4w)
8 = 8w
or w = 1 cm
Then length ,l = 3w =3 * 1 = 3 cm
Hence length of rectangle is 3cm and width of rectangle is 1cm.
