If f(x)=3x^2 +x-2, then f(-2)= 12 -16 8 32 help!

Mathematics

1 answer:

uysha [10]3 years ago

8 0

8 is the answer

Ignore this part, Brainly wants more than 20 characters

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The graph of a sinusoidal function has a minimum point at (0, - 10) and then has a maximum point at (2, - 4) Write the formula o

AleksAgata [21]

Answer: $\bold{y=3sin\bigg(\dfrac{\pi}{2}x-\dfrac{\pi}{2}\bigg)-7}$

<u>Step-by-step explanation:</u>

Minimum: (0, -10)

Maximum: (2, -4)

y = A sin (Bx - C) + D

Amplitude (A) = (Max - Min)/2
Period = 2π/B → B = 2π/Period
Phase Shift = C/B → C = B × Phase Shift
Midline (D) = (Max + Min)/2

$A=\dfrac{-4-(-10)}{2}\quad =\dfrac{-4+10}{2}\quad =\dfrac{6}{2}\quad =\large\boxed{3}$

$\text{x-value of Max minus x-value of Min}= \dfrac{1}{2}\text{Period}\\\\2 - 0 = \dfrac{1}{2}P\quad \rightarrow \quad P=4\\\\\\B=\dfrac{2\pi}{P}\quad =\dfrac{2\pi}{4}\quad =\large\boxed{\dfrac{\pi}{2}}\\$

$D = \dfrac{\text{Max + Min}}{2}\quad = \dfrac{-4+(-10)}{2}\quad =\dfrac{-14}{2}\quad =\large\boxed{-7}$

Sin usually starts at (0, 0). For this graph, the midline touches 0 when x = 1 so the Phase Shift = 1.

$C = B \times \text{Phase Shift}\quad = \dfrac{\pi}{2}\times 1\quad =\large\boxed{\dfrac{\pi}{2}}$

$A=3, \quad B=\dfrac{\pi}{2}, \quad C=\dfrac{\pi}{2},\quad D=-7\\\\\rightarrow \quad \large\boxed{y=3\sin \bigg(\dfrac{\pi}{2}x-\dfrac{\pi}{2}\bigg)-7}$