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Cerrena [4.2K]
3 years ago
9

If f(x)=3x^2 +x-2, then f(-2)= *12 *-16 *8 *32 help!

Mathematics
1 answer:
uysha [10]3 years ago
8 0
8 is the answer

Ignore this part, Brainly wants more than 20 characters
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Identify the 42nd term of an arithmetic sequence where a1 = -12 and a27 = 66
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The arithmetic formula is expressed as an = a1 + d *(n-1)where n is an integer. Substituting from the given a1 = -12 and a27 = 66, 66 = -12 + d *(27-1). hence  , d is equal to 3. a42 thus using the formula is equal to 111. The final answer to this problem is 111.
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Which logarithmic graph can be used to approximate the value of y in the equation 3^y = 4?
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c

Step-by-step explanation:

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Three cards are drawn with replacement from a standard deck. what is the probability that the first card will be a diamond, the
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Complete the sentence.<br><br><br> 7 is 35% of _________.
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What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

4 0
3 years ago
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