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3 years ago

PLEASE HELP ME WITH THIS IT'S DUE TOMORROW

Chemistry

1 answer:

Bond [772]3 years ago

7 0

Answer:

Both:

-They are both made up of cells embedded in an extracellular matrix. It is the nature of the matrix that defines the properties of these connective tissues.

Cartilage:

-Cartilage is thin, avascular, flexible and resistant to compressive forces.

-Cartilages are soft and flexible components present in ear, nose and joints.

Bone marrow:

-Bone is highly vascularised, and its calcified matrix makes it very strong.

-Bones are hard and tough which gives the structural framework of the skeleton in the body.

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A large balloon is initially filled to a volume of 25.0 L at 353 K and a pressure of 2575 mm Hg. What volume of gas will the bal

bija089 [108]

Answer:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 25.0 L

V₂ = ?

P₁ = 2575 mm Hg

Also, P (atm) = P (mm Hg) / 760

P₁ = 2575 / 760 atm = 3.39 atm

P₂ = 1.35 atm

T₁ = 353 K

T₂ = 253 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{3.39}\times {25.0}}{353}=\frac{{1.35}\times {V_2}}{253}$

$\frac{1.35V_2}{253}=\frac{3.39\times \:25}{353}$

Solving for V₂ , we get:

45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.

4 0

4 years ago

3. At 35 C, a sample of gas has a volume of 256 ml and a pressure of 720.torr. What would the volume

STatiana [176]

Answer:

The volume will be 185.83 mL.

Explanation:

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. Gay-Lussac's law can be expressed mathematically as follows:

$\frac{P}{T} =k$

Where P = pressure, T = temperature, k = Constant

Boyle's law says that the volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure. Boyle's law is expressed mathematically as:

P*V=k

Where P = pressure, V = volume, k = Constant

Finally, Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is kept at a constant pressure. For a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement of the gas molecules. .

In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

$\frac{V}{T} =k$

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

$\frac{P*V}{T} =k$

Studying two different states, an initial state 1 and a final state 2, it is satisfied:

$\frac{P1*V1}{T1} =\frac{P2*V2}{T2}$

In this case:

P1= 720 torr
V1= 256 mL
T1= 35 C= 308 K (being 0 C= 273 K)
P2= 1.25 atm= 950 torr (being 1 atm= 760 torr)
V2= ?
T2= 22 C= 295 K

Replacing:

$\frac{720 torr*256 mL}{308 K} =\frac{950 torr*V2}{295 K}$

Solving:

$V2= \frac{295K}{950 torr} *\frac{720 torr*256 mL}{308 K}$

V2= 185.83 mL

<u><em>The volume will be 185.83 mL.</em></u>

6 0

3 years ago

Complete the following calculations regarding acid/base titrations

madam [21]

Based on the information provided and the assumption that the mole ratio of the acid to the base is 1:1, the molarity of the acid would be 0.0425 M

<h3>Acid/base Titration</h3>

Using the equation:

CaVa = CbVb

This is based on the assumption that the stoichiometric mole ratio of the acid to the base is 1:1.

Ca = CbVb/Va

0.1 x 25.5/60 = 0.0425 M

More on acid/base titration can be found here: brainly.com/question/2728613

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3 years ago

You titration 5.0 mL of HCl with 0.010 M NaOH. You find the end point of your titration occurs when 12.0 mL of NaOH has been add

Nookie1986 [14]

your answer is 0.00833M the volume was converted into liters

NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)

Using the molarity equation, we can find the number of moles of HCl that reacted:

molarity=mol soluteL soln

mol solute=(molarity)(L soln)

mol HCl=(0.105molL)(0.0250L)=0.00263 mol HCl

(volume converted to liters)

Now, using the coefficients of the chemical reaction, we can determine the number of moles of NaOH that reacted:

0.00263mol HCl(1lmol NaOH1mol HCl)=0.00263 mol NaOH

Lastly, we'll use the molarity equation (using given volume of NaOH soln) again to determine the molarity of the sodium hydroxide solution:

molarity=mol soluteL soln

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3 years ago

Hello there, in my biology class, we did a bacteria milk lab and my group added yeast to the milk in a test tube for three diffe

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The standard plate count is used to determine the total number of bacteria present in a specified amount of milk, usually a milliliter (mL). This is used for the grading of milk. The coliform plate count is widely used to determine the total number of coliforms present in one mL of milk sample.

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3 years ago