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TEA [102]
3 years ago
8

In the reaction shown, 88.388.3 g salicylic acid, C7H6O3C7H6O3 , reacts with excess acetic anhydride, C4H6O3C4H6O3 , producing 6

2.062.0 g of aspirin, C9H8O4C9H8O4 . C7H6O3(s)+C4H6O3(l)⟶C9H8O4(s)+CH3CO2H(l) C7H6O3(s)+C4H6O3(l)⟶C9H8O4(s)+CH3CO2H(l) Calculate the percent yield of this reaction
Chemistry
1 answer:
Ulleksa [173]3 years ago
6 0

Answer:

53.9%

Explanation:

The equation of the reaction is;

C4H6O3+C7H6O3→C9H8O4+C2H4O2

Number of moles of salicyclic acid reacted = 88.3 g/138.121 g/mol = 0.639 moles

1 mole of salicyclic acid yields 1 mole of aspirin

0.639 moles of salicyclic acid also yields 0.639 moles of asprin

Theoretical yield of asprin = 0.639 moles * 180.158 g/mol

Theoretical yield of asprin = 115.12 g

Percent yield = Actual yield/Theoretical yield * 100/1

Percent yield = 62.0 g/115.12 g * 100

Percent yield = 53.9%

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How can a Hydrogen atom turn into a<br> Hydrogen ion (H+)?
Butoxors [25]

Answer:

By losing an electron

Explanation:

Electrons have a negative charge. So, losing one would give an element a more positive charge. You can usually find a hydrogen ion (H+) in substances like acids.

3 0
3 years ago
____________ properties include melting point, boiling point, strength, and malleability.a.physicalc.chemicalb.reactived.none of
lina2011 [118]
Physical properties are those which can be observed without any change in composition of the substance. Hence, a is the answer.
8 0
4 years ago
a 22.44g sample of iron absorbs 180.8 J of heat, upon which the temperature of the sample increases from 21.1C to 39.0/ what is
NeX [460]

Answer:

The specific heat of iron is 0.45 J/g.°C

Explanation:

The amount of heat absorbed by the metal is given by:

heat = m x Sh x ΔT

From the data, we have:

heat = 180.8 J

mass = m = 22.44 g

ΔT = Final temperature - Initial temperature = 39.0°C - 21.1 °C = 17.9°C

Thus, we calculate the specific heat of iron (Sh) as follows:

Sh = heat/(m x ΔT)  = (180.8 J)/(22.44 g x 17.9°C) = 0.45 J/g.°C

8 0
3 years ago
A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm
Ulleksa [173]

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100

Percent error = \frac{0.1}{63.2}\times 100

Percent error = 0.00158\times 100

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100

Percent error = \frac{0.2}{63.2}\times 100

Percent error = 0.00316\times 100

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100

Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100

Percent error = \frac{(0.5)}{63.2}\times 100

Percent error = 0.00791\times 100

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%




7 0
4 years ago
A solution is made by mixing 37.g of thiophene C4H4S and 72.g of heptane C7H16. Calculate the mole fraction of thiophene in this
guajiro [1.7K]

Answer:

0.38

Explanation:

Molar mass of thiophene= 84g/mol

Mass of thiophene = 37g

Number of moles= 37/84= 0.44 moles

Molar mass of heptane= 100 g/mol

Mass of heptane = 72g

Number of moles = 72/100= 0.72 moles

Total number of moles= 0.44 + 0.72= 1.16 moles

mole fraction of thiophene = 0.44/1.16= 0.38

4 0
3 years ago
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