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TEA [102]
3 years ago
8

In the reaction shown, 88.388.3 g salicylic acid, C7H6O3C7H6O3 , reacts with excess acetic anhydride, C4H6O3C4H6O3 , producing 6

2.062.0 g of aspirin, C9H8O4C9H8O4 . C7H6O3(s)+C4H6O3(l)⟶C9H8O4(s)+CH3CO2H(l) C7H6O3(s)+C4H6O3(l)⟶C9H8O4(s)+CH3CO2H(l) Calculate the percent yield of this reaction
Chemistry
1 answer:
Ulleksa [173]3 years ago
6 0

Answer:

53.9%

Explanation:

The equation of the reaction is;

C4H6O3+C7H6O3→C9H8O4+C2H4O2

Number of moles of salicyclic acid reacted = 88.3 g/138.121 g/mol = 0.639 moles

1 mole of salicyclic acid yields 1 mole of aspirin

0.639 moles of salicyclic acid also yields 0.639 moles of asprin

Theoretical yield of asprin = 0.639 moles * 180.158 g/mol

Theoretical yield of asprin = 115.12 g

Percent yield = Actual yield/Theoretical yield * 100/1

Percent yield = 62.0 g/115.12 g * 100

Percent yield = 53.9%

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\begin{aligned}K_{\rm a} &= \frac{[{\rm H}^{+}] \cdot [{\rm A}^{-}]}{[{\rm HA}]} \\ &= \frac{(0.09125\; \rm mol \cdot L^{-1}) \times (0.09125\; \rm mol \cdot L^{-1})}{0.63875\; \rm mol \cdot L^{-1}}\\[0.5em]&\approx 1.30 \times 10^{-2} \end{aligned}.

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