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TEA [102]
3 years ago
8

In the reaction shown, 88.388.3 g salicylic acid, C7H6O3C7H6O3 , reacts with excess acetic anhydride, C4H6O3C4H6O3 , producing 6

2.062.0 g of aspirin, C9H8O4C9H8O4 . C7H6O3(s)+C4H6O3(l)⟶C9H8O4(s)+CH3CO2H(l) C7H6O3(s)+C4H6O3(l)⟶C9H8O4(s)+CH3CO2H(l) Calculate the percent yield of this reaction
Chemistry
1 answer:
Ulleksa [173]3 years ago
6 0

Answer:

53.9%

Explanation:

The equation of the reaction is;

C4H6O3+C7H6O3→C9H8O4+C2H4O2

Number of moles of salicyclic acid reacted = 88.3 g/138.121 g/mol = 0.639 moles

1 mole of salicyclic acid yields 1 mole of aspirin

0.639 moles of salicyclic acid also yields 0.639 moles of asprin

Theoretical yield of asprin = 0.639 moles * 180.158 g/mol

Theoretical yield of asprin = 115.12 g

Percent yield = Actual yield/Theoretical yield * 100/1

Percent yield = 62.0 g/115.12 g * 100

Percent yield = 53.9%

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How much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh
Sever21 [200]

Answer:

13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

Volume of the acid (Va) =?

Volume of the base (Vb) = 39mL

Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

6 x Va / 2 x 39 = 1/1

Cross multiply to express in linear form

6 x Va = 2 x 39

Divide both side by 6

Va = (2 x 39)/6

Va = 13mL

Therefore, the volume of the acid (HNO3) needed for the reaction is 13mL

5 0
3 years ago
Ten lab safety rules
Bogdan [553]
Don't touch your eyes.

Never taste-test unless the teacher tells you to.

Do not touch anything without directions.

Wear safety goggles. 

Wash your hands after each experiment.

Wear proper lab clothes.

Do not mishandle lab equipment.

Clean up your workplace.

Act serious; no horseplay!

Report accidents to the teacher right away!


Have a great day, scholar! 
4 0
3 years ago
Write the formula for Zn+2 (SO4)-2
Pie

Answer:

Zn2 + SO4 = Zn2(SO4)2

Explanation:

4 0
3 years ago
How much energy is required to raise the temperature of 10.7 grams of gaseous helium from 22.1 °C to 39.4 °C ?
Rainbow [258]

Answer:

Q = 2640.96 J

Explanation:

Given data:

Mass of He gas = 10.7 g

Initial temperature = 22.1°C

Final temperature = 39.4°C

Heat absorbed = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree. Specific heat capacity of He is 14.267 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 39.4°C - 22.1°C

ΔT = 17.3°C

Q = 10.7 g× 14.267 J/g.°C ×  17.3°C

Q = 2640.96 J

5 0
3 years ago
If you want to lift a 30-kg box to a height of 1 m, how much work will it take?
natta225 [31]

Explanation:

workdone = force x distance

force = mass x acceleration

30 x 10 = 300N

300N x 1m

workdone= 300J

7 0
3 years ago
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