So,
To compose a function with another, substitute the inside function into every place where x appears in the outer function.
For (h * h)(x), substitute h(x) for every x in the outer function, h(x).
![h(x)=\frac{6}{x}-->(h^oh)(x)=\frac{6}{\frac{6}{x}}=6*\frac{x}{6}=x](https://tex.z-dn.net/?f=h%28x%29%3D%5Cfrac%7B6%7D%7Bx%7D--%3E%28h%5Eoh%29%28x%29%3D%5Cfrac%7B6%7D%7B%5Cfrac%7B6%7D%7Bx%7D%7D%3D6%2A%5Cfrac%7Bx%7D%7B6%7D%3Dx)
For (f * f)(x), substitute f(x) for every x in the outer function, f(x).
![f(x)=x^2-5-->(f^of)(x)=(x^2-5)^2-5=x^4-10x^2+20](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-5--%3E%28f%5Eof%29%28x%29%3D%28x%5E2-5%29%5E2-5%3Dx%5E4-10x%5E2%2B20)
Hope this helps!
Answer:
D). (n + 4)^3/5.
Step-by-step explanation:
The fifth root is equal to exponent 1/5 and the n + 4 is taken to the power 3 so the answer is (n + 4)^3/5.
I would travel 40hours. 16 times two is 32 plus 8 is 40.
31/33 is in simplest form because both 31 and 33 do not have a common factor that be used to simplify.
Factorized: (a + b + 2) ^2