Check the picture below.
so the surface area of the pyramid will be the sum of the areas of the base and the four triangular faces.
![\stackrel{\textit{\Large Areas}}{\stackrel{\textit{4 triangular faces}}{4\left[ \cfrac{1}{2}(7.5)(16) \right]}~~ + ~~\stackrel{\textit{rectangular base}}{(7.5)(7.5)}}\implies 240~~ + ~~56.25\implies 296.25~ft^2](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7B%5CLarge%20Areas%7D%7D%7B%5Cstackrel%7B%5Ctextit%7B4%20triangular%20faces%7D%7D%7B4%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%287.5%29%2816%29%20%5Cright%5D%7D~~%20%2B%20~~%5Cstackrel%7B%5Ctextit%7Brectangular%20base%7D%7D%7B%287.5%29%287.5%29%7D%7D%5Cimplies%20240~~%20%2B%20~~56.25%5Cimplies%20296.25~ft%5E2)
There are 520'pages in the whole book because if you divide 390 by 3 you get 130 and if you multiply that by 4 you get 520, hope this helps! Please give brainiest answer and say thanks.
Answer:
(9, 3)
Step-by-step explanation:
When a point is rotated 180 degrees, you take the opposite of the coordinates.
i.e (5, 6) ---> (-5, -6)
Answer:
3
Step-by-step explanation:
f(3)=2(3)-3
You just plug in the number for the variable.
Answer:
Step-by-step explanation:
Begin
If this is a rhombus then <8 = 90 degrees as do all the central angles. That's because the diagonals intersect at right angles.
<4 = 38 z formation for parallel lines.
<7 = 52 The angles are part of a right angle triangle. <7 +38 = 90
<2 = 52 z formation of parallel lines (a rhombus has ll lines).
<3 = 38 The diagonals of a rhombus bisect each other.
<5 = 38 z formation for parallel lines.
<6 = 52 The diagonals of a rhombus are angle bisectors.
<1 = 52 The diagonals of a rhombus are angle bisectors.
