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Free_Kalibri [48]
3 years ago
6

What’s the answer pls

Mathematics
1 answer:
larisa [96]3 years ago
3 0
Amount of interest = 3/100 x 1200
= $36

Answer is B
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Between t=10 and t=60 the acceleration is 0.4 calculate the speed when t=60​
Lisa [10]

Answer:

i dont understand

Step-by-step explanation:

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3 years ago
Each coach has 50 seats and there are 1030 supporters. How many coaches are needed to take all the supporters?
alisha [4.7K]
The answer would be to divide 1030 by 50 and you would get 21 coaches not 20 because 50x20=1000 and there are 30 remainder. Therefor, you would need that extra coach with some seats left to spare. so your answer is 21 coaches
6 0
3 years ago
7. Find the value of Z in the following equation: 8Z = 64.
Effectus [21]
Z=8 because you have to get z by itself therefore you have to divide 8 on both sides leaving z to equal 8
4 0
3 years ago
Read 2 more answers
Gina, Sam, and Robby all rented movies from the same video store. They each rented some dramas, comedies, and documentaries. Gin
weqwewe [10]
Solve using equations:

Gina 11 = a+b+c
Sam 27 = 2a+3b+2c
Robby 19= a+2b+2c

Gina *2 give 22=2a+2b+2c (subtract this from Sam to give)
b=5

the subtract Robby from Gina *2 to give a=3



[Question 1]
let d = number of dramas Gina rented, c = # of comedies, and t = # of documentaries:

[equation a] d + c + t = 11
[equation b] 2d + 3c + 2t = 27
[equation c] d + 2c + 2t = 19

if we subtract [a] from [c] we get:
[equation d] c + t = 8

if we subtract [c]*2 from [b] we get:
[equation e] -c - 2t = -11 or
[equation e] c + 2t = 11

Now we can subtract [e] from [d] to solve for t:
t = 3

Now put in 3 for t in [d] or [e] to solve for c:
c + 2(3) = 11
c + 6 = 11
c = 5

So she rented 5 comedies and 3 documentaries which leaves 3 dramas (which is answer A)
6 0
3 years ago
Read 2 more answers
25. Michael is studying population changes in two
g100num [7]

Answer: Average rates of change for Bird A is 0.045 and for Bird B is 3.816.

Step-by-step explanation: Through its graph, a function can be analyzed and be identified its attributes. Average Rate of Change is the ratio of change in the function values to the change of x-value, i.e., it is the slope of the function in a specific interval of x. With the Average it is possible to compare two function.

<u>Average Rate of Change</u>

<em><u>Bird A</u></em>:

For the interval [0,18]:

x₁ = 0 f(0) = 8.3

x₂ = 18 f(18) = 9.1

Average = \frac{f(18) - f(0)}{x_{2} - x_{1} }

Average = \frac{9.1 - 8.3}{18 - 0}

Average = 0.045

<em><u>Bird B</u></em>: y = 3.6(1.06)x

For the interval [0,18]:

x₁ = 0 y = 3.6(1.06)0 = 0

x₂ = 18 y = 3.6(1.06)18 = 68.7

Average = \frac{f(18) - f(0)}{x_{2} - x_{1} }

Average = \frac{68.7 - 0}{18 - 0}

Average = 3.816

The Average Rate for Change for Bird A is 0.045 and for Bird B is 3.816. This means that the population of Bird B increase in rate faster than the population of Bird A.

4 0
3 years ago
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