1. B
2. D) 2/7 teaspoons
3. D) $.90
The guts of the table are ...
![\left[\begin{array}{cccc}x&y&x+y=85&y=2x+4\\19&65&\text{false}&\text{false}\\25&60&\text{true}&\text{false}\\27&58&\text{true}&\text{true}\\32&53&\text{true}&\text{false}\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7Dx%26y%26x%2By%3D85%26y%3D2x%2B4%5C%5C19%2665%26%5Ctext%7Bfalse%7D%26%5Ctext%7Bfalse%7D%5C%5C25%2660%26%5Ctext%7Btrue%7D%26%5Ctext%7Bfalse%7D%5C%5C27%2658%26%5Ctext%7Btrue%7D%26%5Ctext%7Btrue%7D%5C%5C32%2653%26%5Ctext%7Btrue%7D%26%5Ctext%7Bfalse%7D%5Cend%7Barray%7D%5Cright%5D%20%20)
Of course, you know the answer after figuring the third line of the table.
The two numbers are 27 and 58.
_____
If the second number is odd, the result after subtracting 4 will not be divisible by 2. This lets you reject the 1st and 4th choices immediately. As for the second choice, twice 25 is 10 less than 60, not 4 less, so that choice can also be discarded.
Starting from the system of equations

you can use substitution to get

This identifies the 3rd selection as the appropriate one.
Answer:
t = 3h
Step-by-step explanation:
Given
h =
t
Multiply both sides by 3 to clear the fraction
3h = t
(4x+3) (2x-5)
8x^2-20x+6x-15
8x^2-14x-15
The
expression is: | x | = A + B + (A < C < B)
To simplify
the expression, write without the absolute value sign and we
would get this:
<span>x = A + B +
(A < C < B)</span>