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marusya05 [52]
3 years ago
14

Please help!! I have no clue how to do this

Mathematics
2 answers:
devlian [24]3 years ago
3 0

Answer:

Step-by-step explanation:

you need the arc length formula .. do you have it?

s = r ∅

s  is the arc length in radians but you can make it in degrees just by

using    s = 2πr (θ/360)

the angle is 180 for the picture.

so the arc length is just  \pir

r= 4

\pi*4 = 12.56637.... approx

anygoal [31]3 years ago
3 0

Answer:

s  is the arc length in radians but you can make it in degrees just by

using    s = 2πr (θ/360)

angles 180 for the picture.

arc length is just  r

r= 4

4 = 12.5

Step-by-step explanation:

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The top letter is “L”<br> Please help!! Answer correctly and no guessing, please!
Mkey [24]

First you need to find out what K and L's angle is

Step #1: Finding L's angle number

to do this you are going to subtract  219-178=?

answer should be 41.

Step #2: Desiding if J is Larger than L

Is 219 Larger than 41? or is 41 larger than 219?

4 0
3 years ago
Read 2 more answers
5. For the data in the table below, find the sum of the absolute deviations for the predicted values
Kipish [7]

Based on the absolute deviations and the predicted values, the sum of absolute deviations will be <u>4.8.</u>

<h3>What would be the sum of absolute deviations from predicted values?</h3>

This can be found as:

= ∑ (Observed value - Predicted value)

The observed values are given in the table and the predicted values will be calculated using y = 3.6x - 0.4.

Solving gives:

=  [3 - (3.6 x 1 - 0.4)] + [7 - (3.6 x 2 - 0.4)] + [ 9 - (3.6 x 3 - 0.4)] + [14 - (3.6 x 4 - 0.4)] + [15 - (3.6 x 5 - 0.4)] + [21 - (3.6 x 6 - 0.4)] + [25 - (3.6 x 7 - 0.4)]

= 0.2 + 0.2 + 1.4 + 0 + 2.6 + 0.2 + 0.2

= 4.8

Find out more on absolute deviation at brainly.com/question/447169.

4 0
2 years ago
1 /4x² = - 1/2x + 2?
Sphinxa [80]

Answer:

x1=-4 x2=2

Step-by-step explanation:

5 0
3 years ago
Line d is parallel to line c in the figure below.
bekas [8.4K]

Answer:

Its the 2nd, 3rd, and 4th answer.

Step-by-step explanation:

: )

Have a great day.

Do you want a explanation?

4 0
3 years ago
The energy information administration reported that the mean retail price per gallon of regular grade gasoline was $3.43. Suppos
Morgarella [4.7K]

Answer:

68.26% of regular grade gasoline sold between $3.33 and $3.53 per gallon

81.85% of regular grade gasoline sold between $3.33 and $3.63 per gallon

2.28% of regular grade gasoline sold for more than $3.63 per gallon

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 3.43, \sigma = 0.1

What percentage of regular grade gasoline sold between $3.33 and $3.53 per gallon?

This is the pvalue of Z when X = 3.53 subtracted by the pvalue of Z when X = 3.33. So

X = 3.53

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.53 - 3.43}{0.1}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 3.33

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.33 - 3.43}{0.1}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% of regular grade gasoline sold between $3.33 and $3.53 per gallon

What percentage of regular grade gasoline sold between $3.33 and $3.63 per gallon?

This is the pvalue of Z when X = 3.53 subtracted by the pvalue of Z when X = 3.33. So

X = 3.63

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.63 - 3.43}{0.1}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 3.33

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.33 - 3.43}{0.1}

Z = -1

Z = -1 has a pvalue of 0.1587

0.9772 - 0.1587 = 0.8185

81.85% of regular grade gasoline sold between $3.33 and $3.63 per gallon

What percentage of regular grade gasoline sold for more than $3.63 per gallon?

This is 1 subtracted by the pvalue of Z when X = 3.63. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.63 - 3.43}{0.1}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% of regular grade gasoline sold for more than $3.63 per gallon

3 0
3 years ago
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