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3 years ago

15

HELP HELP HELP PLEASE!!!! Ryan sells beaded necklaces. Each large necklace sells for $4.10 and each small necklace sells for $3.

80. How much will he earn from selling 1 large necklace and 5 small necklaces?

1 answer:

leonid [27]3 years ago

4 0

Answer:

$23.01

Step-by-step explanation:

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32=32+? I need help its annoyings

Andreyy89

Answer:

0

Step-by-step explanation:

32=32+0

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3 years ago

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which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

Nutka1998 [239]

Answer:

$\frac{\sqrt[3]{16y^4}}{x^2}$

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices $\sqrt[n]{a} = a^{\frac{1}{n}}$

So,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ gives

$\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}$

Also from laws of indices

$(ab)^n = a^nb^n$

So, the above expression can be further simplified to

$\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}$

Multiply the exponents gives

$\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

Substitute $2^5$ for 32

$\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

From laws of indices

$\frac{a^m}{a^n} = a^{m-n}$

This law can be applied to the expression above;

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$ becomes

$2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}$

Solve exponents

$2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}$

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$

From laws of indices,

$a^{-n} = \frac{1}{a^n}$ ; So,

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$ gives

$\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}$

The expression at the numerator can be combined to give

$\frac{(2y)^{\frac{4}{3}}}{x^2}$

Lastly, From laws of indices,

$a^{\frac{m}{n} = \sqrt[n]{a^m}$ ; So,

$\frac{(2y)^{\frac{4}{3}}}{x^2}$ becomes

$\frac{\sqrt[3]{(2y)}^{4}}{x^2}$

$\frac{\sqrt[3]{16y^4}}{x^2}$

Hence,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ is equivalent to $\frac{\sqrt[3]{16y^4}}{x^2}$

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3 years ago

Help will give Brainly points

masya89 [10]

Answer:

x=√14

Step-by-step explanation:

Hi there!

We are given a right triangle (notice the right angle), with acute angles measuring 45° and 45°, the hypotenuse (the side opposite from the right angle) labeled as x, and one of the legs (one of the sides that makes up the right angle) labeled as √7

As these two angles are the same measure, the triangle is isosceles.

So that means that the measure of the other leg (the unmarked side) is also √7.

This triangle is a special type of triangle; a 45°-45°-90° triangle. For this triangle, if the length of the legs are a, then the hypotenuse has the length a√2

In this case, √7 is a, and as x is the measure of the hypotenuse, it must be equal to a√2, which substituting the values of a would get √7 * √2, which is √14.

The radical cannot be simplified further, so √14 is the answer.

Hope this helps!

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3 years ago

Solve the following equation. 7(x - 2) = 3(x + 4)

scoray [572]

Answer:

x = 6.5

Step-by-step explanation:

You have to apply the distributive property of multiplication:

7(x-2) = 3(x+4)

7x - 14 = 3x + 12

7x - 3x = 12 + 14

4x = 26

x = 6.5

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3 years ago

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a trader bought 5 apples,7 oranges,5 pawpaw fruit,10 pineapples and 3 guava fruit to the market for sale.find the probability th

garri49 [273]

1/3 is the probability

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4 years ago