9514 1404 393
Answer:
15
Step-by-step explanation:
In vector form, the equation of point p on the line can be written as ...
p = (-3, -4) +t(25 -(-3), 38 -(-4)) . . . . . for some scalar t
p = (-3, -4) +t(28, 42)
p = (-3, -4) +14t(2, 3)
where t takes on any value between 0 and 1.
If we let t = n/14 for some integer 0 ≤ n ≤ 14, then the coordinates of point p will be integers.
There are 15 values that n can have in the allowed range.
The caterpillar touches 15 points with integer coordinates.
(0,-7)
-7=11(0)+4
-7=0+4
-7 is not 4 -----not a solution
(-1,-7)
-7=11(-1)+4
-7=-11+4
-7=-7 ----solution
(1,-7)
-7=11(1)+4
-7=11+4
-7=15
-7 is not 15 ----not a solution
(2,26)
26=11(2)+4
26=22+4
26=26 ----soltion
(-1, -7) & (2, 26) are solutions to the equation
F(2y + 1) is 2
+
for this question
17/33 in lowest terms<span>
17/33 is in lowest terms. It cant be divided any farther.
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Answer:
x= 48 and PMO= 55
Step-by-step explanation:
PMO= LMO so 55= x+7
x+7=55
-7 -7
x=48
Pmo = x+7 so (48)+7 = 55
