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lana [24]
3 years ago
14

If x + 4 = 32, does x = 8?

Mathematics
1 answer:
miss Akunina [59]3 years ago
7 0

Answer:

No

Step-by-step explanation:

I say no because if we were to replace x with 8, the equation should look like this = 8 + 4 = 32. Since this doesn't make sense, 8 cannot be x. X would be 28 which would equal 32 and would be the right answer.

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What is the semimonthly salary when the weekly salary is $ 650.00?
mina [271]

weekly salary is 650$

the number of days in a week is 7.

7 days salary is 650$

one day salary is 650/7

the number of days in semi month is 30/2 = 15 days

so the salary of semi month is 15*650/7 = 1392.85 $

so the salary of semi month is 1392.85 $.

4 0
1 year ago
If Angle A = 5x-10, find the value(s) for x that would ensure that Angle A was an obtuse angle.
morpeh [17]

Answer:

20 < x < 38.

Step-by-step explanation:

An obtuse angle has a value between 90 and 180.

90 < 5x - 10 < 180

5x - 10 > 90

5x > 100.

x > 20.

5x - 10< 180

5x < 190

x < 38

3 0
4 years ago
Assume that the following statements are true.
kondaur [170]
Anna is drinking ice tea, in C, it states, ”If it is dinnertime, then Anna is drinking iced tea and nothing else.” therefore proving that she is drinking iced tea, furthermore verifying that it is dinnertime.
4 0
4 years ago
What is 2 3/2 equal to?
Setler79 [48]

For this case we have the following expression:

2 ^ {\frac {3} {2}}

We must indicate an equivalent expression. By definition of properties of powers and roots we have:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

Then, rewriting the expression:2 ^ {\frac {3} {2}} = \sqrt {2 ^ 3} = \sqrt {8}

Then, the expression is equivalent to the square root of 8.

ANswer:

Square root of 8.

6 0
3 years ago
6. Find the product for both sets of polynomials below by multiplying vertically.
stiv31 [10]

Answer:

A) 4x^5-4x^4-16x^2+16x

B) 4x^4-4x^3-16x^2+16x

Also, maybe that vertically means:

A) 4x^2 \cdot x^3    and (-4x) \cdot (-4)

Resulting in 4x^5+16x

B) x^2 \cdot 4x^2    and  x \cdot (-8x)  and -2 \cdot 0

Resulting in 4x^4-8x^2

Step-by-step explanation:

It seems that you want to multiply the polynomials in this way: (\text{Polynomial - 1})\cdot(\text{Polynomial - 2})

A)

4x^2-4x

x \cdot x^2 -4

(4x^2-4x)(x \cdot x^2 -4)=(4x^2-4x)(x^3 -4)

(4x^2-4x)(x^3 -4)\\

4x^5-16x^2-4x^4+16x

4x^5-4x^4-16x^2+16x

B)

x^2+x-2

4x^2-8x

(x^2+x-2)(4x^2-8x)

4x^4-8x^3+4x^3-8x^2-8x^2+16x

4x^4-4x^3-16x^2+16x

6 0
3 years ago
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