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Lana71 [14]
3 years ago
13

Help ASAP!!!! Plsssss

Mathematics
2 answers:
Readme [11.4K]3 years ago
8 0

Answer:

2. y = 4x+7; y=-7x+5

Step-by-step explanation:

Andrei [34K]3 years ago
7 0

Answer:

yea the second one is correct

Step-by-step explanation:

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The graph shows the relationship between the number of granola bars and amount of calories per bar.
castortr0y [4]

part a y= x × 100

Step-by-step explanation:

1 bar is 100 calories so you would times it by 100 for every bar

5 0
3 years ago
Answer 7, 8, 9, 10. <br> I am giving out a 5- star rating! and marking u brainy if its right!
UNO [17]
7. Four and 7 tenths
8. Twenty two and eighty nine hundredths
9. Forty Five and Three hundred Twenty Nine Thousandths
10.Twenty seven hundredths
3 0
3 years ago
Can 12,18,30 be a right triangle
ASHA 777 [7]

Answer:

no

Step-by-step explanation:

A set of three integers that can be the lengths of the sides of a right triangle is called a Pythagorean triple. The simplest Pythagorean triple is the set “3, 4, 5.” These numbers are the lengths of the sides of a “3-4-5” Pythagorean right triangle. The list below contains all of the Pythagorean triples in which no number is greater than 50.

3, 4, 5

5, 12, 13 6, 8, 10

7, 24, 25 8, 15, 17 9, 12, 15 9, 40, 41 10, 24, 26 12, 16, 20 12, 35, 37

14, 48, 50 15, 20, 25 15, 36, 39 16, 30, 34 18, 24, 30 20, 21, 29 21, 28, 35 24, 32, 40 27, 36, 45 30, 40, 50

Example Problems

Find the length of the missing side.

13 25 x7

12 x

From the list above, the missing From the list above, the missing side is “5” side is “24”

Show why the set “6,8,10” is a Pythagorean triple.

c2 = a2 + b2 102 =82 +62 100 = 64 + 36 100 = 100

Since the Pythagorean equation is satisfied, the set “6,8,10” is a Pythagorean triple.

7 0
3 years ago
Read 2 more answers
Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''
Nonamiya [84]

Answer:

a-e^x,e^{-x}

b-x^{-2}

c-x^3

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

D^2-1=0

(D-1)(D+1)=0

D=1,-1

Then , the solution of given differential equation

y=e^x,y=e^{-x}

2.7x^2y''+14xy'-14 y=0

Y=y=x^3

y=3x^2

y''=6x

Substitute in the given differential equation

42x^3+42x^3-14x^3\neq 0

Hence, x^3 is not a solution of given differential equation

e^x,e^{-x} are also not a solution of given differential equation.

y=x^{-2}

y'=-2x^{-3}

y''=6x^{-4}

Substitute the values in the differential equation

7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}

=42x^{-2}-28x^{-2}-14x^{-2}=0

Hence, x^{-2} is a solution of given differential equation.

c.7x^2y''-42y=0

y=x^3

y'=3x^2

y''=6x

Substitute the values in the differential equation

42x^3-42x^3=0

Hence, x^3 is a solution of given differential equation.

a-e^x,e^{-x}

b-x^{-2}

c-x^3

6 0
4 years ago
Read 2 more answers
Kimi and her brother saved up for a board game. Kimi saved 8 dollars and her brother saved 7 dollars. together they bought the b
aniked [119]

Answer:

$3

Step-by-step explanation:

8 + 7 = 15

15 - 12 = 3

6 0
3 years ago
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