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harkovskaia [24]
3 years ago
15

hi i am scared of the dak and i am only 7 and i think moster in my closet he is etaing all of my fruit snaks please help me out

i am seirioues
Mathematics
1 answer:
Ivahew [28]3 years ago
7 0

Answer:

sometimes you think that but it's not real and your fruit snacks are just being eaten by furry fat mice sugar WILL attract ants

Step-by-step explanation:

have a good day

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Jason’s salary and Karen’s salary were each p percent greater in 1998 than in 1995. What is the value of p ? (1) In 1995 Karen’s
shtirl [24]

Answer: Hi, first lets give our variables some names.

Lets call Ks to Karen's salary and Js to Jason's salary.

then, in 1995:

Ks₁ - Js₁ = 2000$

in 1998:

Ks₂ - Js₂ = 2440$

now, we know that  Ks₂ = (1 +p)*Ks₁ and   Js₂ = (1+p)*Js₁

so we can write the second equation as:

p*(Ks₁ - Js₁ ) = 2440$

replacing the parentesis with the first equiation

(1+p)*(2000$) = 2440$

(1+p)= 2440/2000 = 1.22

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Answer:

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Step-by-step explanation:

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EleoNora [17]
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David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

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32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

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b^4= b × b × b × b

b^2 = b × b

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GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

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3 years ago
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