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andrey2020 [161]
2 years ago
9

X+3=-6+4x helppp asap pleaseee

Mathematics
2 answers:
Harman [31]2 years ago
5 0

Answer:

x=3

Step-by-step explanation:

Novay_Z [31]2 years ago
5 0

Answer:

3 hope this helps and brainly makes me write an answer with 20 letters so im just typing random stuff

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4) A random sample of students at Westcott Elementary were asked how many siblings they had. The following data was collected: 0
netineya [11]
A) 0
B) 6
C) middle number, or middle 2, averaged, so 3
D) 1
E) 4
F) 6-0 = 6
6 0
3 years ago
An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
uranmaximum [27]

Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

7 0
3 years ago
PLZ HELP ME IDK WUT IT IS!
Simora [160]

Answer:

1.  c. 628 cubic cm

2.  c. 502 cubic inches

Step-by-step explanation:

V=\pi r^{2} h\\

1.)  3.14 x 5^2 x 8

3.14 x 25 x 8 = 628

2.)  3.14 x ( 8/2 )^2 x 10

3.14 x 4^2 x 10

3.14 x 16 x 10 = 502.4

5 0
3 years ago
A particular sale involves four items randomly selected from a large lot that is known to contain 9% defectives. Let X denote th
umka2103 [35]

Answer:

The expected repair cost is $3.73.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of defectives among the 4 items sold.

The probability of a large lot of items containing defectives is, <em>p</em> = 0.09.

An item is defective irrespective of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 9 and <em>p</em> = 0.09.

The repair cost of the item is given by:

C=3X^{2}+X+2

Compute the expected cost of repair as follows:

E(C)=E(3X^{2}+X+2)

        =3E(X^{2})+E(X)+2

Compute the expected value of <em>X</em> as follows:

E(X)=np

         =4\times 0.09\\=0.36

The expected value of <em>X</em> is 0.36.

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)

         =4\times 0.09\times 0.91\\=0.3276\\

The variance of <em>X</em> is 0.3276.

The variance can also be computed using the formula:

V(X)=E(Y^{2})-(E(Y))^{2}

Then the formula of E(Y^{2}) is:

E(Y^{2})=V(X)+(E(Y))^{2}

Compute the value of E(Y^{2}) as follows:

E(Y^{2})=V(X)+(E(Y))^{2}

          =0.3276+(0.36)^{2}\\=0.4572

The expected repair cost is:

E(C)=3E(X^{2})+E(X)+2

         =(3\times 0.4572)+0.36+2\\=3.7316\\\approx 3.73

Thus, the expected repair cost is $3.73.

4 0
3 years ago
Which number line represents the solution set for the inequality 2x- 6&gt;6 (x-2)+8
kirill [66]

Answer:

The inequality is

2 x - 6 > 6(x -2) +8

To solve the inequality we will first use distributive property with respect to multiplication over subtraction

And then bring constant on one side and variable on another side keeping the inequality maintained

2 x -6 > 6 x -12 + 8

2 x -6 > 6 x - 4

6 x - 2 x< -6+4

4 x < -2

Dividing both sides by 2

x <  \frac{-1}{2}

Now i will draw the graph of above function.



8 0
2 years ago
Read 2 more answers
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