So car A travels Distance = 60 km/hr*(1+x)
Car B travels Distance = 75 km/hr(x)
Where x is the time in hours.
Those two equations are equal when on overtakes the other
so:
60 +60x = 75x
60=15x
x=4, but my expression is written to count from when car B commenced travel. So total time is 5 hours from the car A setting off.
I believe its B
i hope this helps :)
Answer:
x = 12
m(QS) = 52°
m(PD) = 152°
Step-by-step explanation:
Recall: Angle formed by two secants outside a circle = ½(the difference of the intercepted arcs)
Thus:
m<R = ½[m(PD) - m(QS)]
50° = ½[(12x + 8) - (4x + 4)] => substitution
Solve for x
Multiply both sides by 2
2*50 = (12x + 8) - (4x + 4)
100 = (12x + 8) - (4x + 4)
100 = 12x + 8 - 4x - 4 (distributive property)
Add like terms
100 = 8x + 4
100 - 4 = 8x
96 = 8x
96/8 = x
12 = x
x = 12
✔️m(QS) = 4x + 4 = 4(12) + 4 = 52°
✔️m(PD) = 12x + 8 = 12(12) + 8 = 152°
Answer: y=1/2x−2
Step-by-step explanation:
Solve the equation.
m+34=m−6
Enter the correct answer in the box.
