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3 years ago

Find the first & second derivative for the function below!

Mathematics

1 answer:

Vesna [10]3 years ago

7 0

Answer:

Step-by-step explanation:

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Find x. Round your answer to the nearest tenth of a degree.<br> x

NeTakaya

Answer:

x ≈ 48.2°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos x = $\frac{adjacent}{hypotenuse}$ = $\frac{6}{9}$ , then

x = $cos^{-1}$ ( $\frac{6}{9}$ ) ≈ 48.2° ( to the nearest tenth )

5 0

3 years ago

Factorise (x-y)^2-(x-y)^3=?

bogdanovich [222]

Answer:

$\left(x-y\right)^2\left(1-x+y\right)$

Step-by-step explanation:

You factor out the common term first.

You should get the equation below.

$\left(x-y\right)^2\left(1-\left(x-y\right)\right)$

then you get rid of the negative inside $\left(1-\left(x-y\right)\right)$

and will be simplified to this.

$\left(x-y\right)^2\left(1-x+y\right)$

4 0

3 years ago

Let f(x) = x - 3 and g(x) = x + 11 find f(x) times g(x)<br><br> What is the answer?

notsponge [240]

f(x) *g(x) = (x-3)(x+11) = x^2 +11x -3x -33 = x^2 +8x -33

Sorry if its wrong :(

6 0

3 years ago

AB and BC form a right angle at point B. If A = (-3,-1) and B = (4,4), what is the equation of BC

m_a_m_a [10]

Answer:

$y=-1.4x+9.6$

Step-by-step explanation:

If A = (-3,-1) and B = (4,4), the slope of AB is

$\text{Slope}_{AB}=\dfrac{-1-4}{-3-4}=\dfrac{-5}{-7}=\dfrac{5}{7}$

Two perpendicular lines have slopes that have product of -1:

$\text{Slopee}_{AB}\cdot \text{Slope}_{BC}=-1\\ \\\dfrac{5}{7}\cdot \text{Slope}_{BC}=-1\\ \\\text{Slope}_{BC}=-\dfrac{7}{5}=-1.4$

The equation of the line BC with slope -1.4 and passing through the point B(4,4) is

$y-4=-1.4(x-4)\\ \\y-4=-1.4x+5.6\\ \\y=-1.4x+9.6$

7 0

4 years ago

Please help it is due in a few mintues

Wittaler [7]

What do I answer .__.

6 0

3 years ago

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