Answer:
Step-by-step explanation:
For a triangle the area is
![A=\frac{1}{2}bh](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7Dbh)
If our triangle is isosceles and the 2 congruent sides each measure 4 and they include an angle of 40 degrees, let's say that the vertex angle is 40 and the sides that are not the base each measure 4. If we drop an altitude from the vertex to the base, we cut the triangle into 2 right triangles, with the vertex angle being 20 degrees and the hypotenuse being 4. To find the base, then, which is opposite the angle, we use the sin ratio:
and
4sin(20) = b so
b = 1.368
But we need the whole base, and that is only half of it. So
2b = 2.736
To find the height, which is adjacent to the angle, we use the cos ratio:
and
4cos(20) = h so
h = 3.759
Now we have enough info to find the area of the triangle using the triangle area formula from above:
and
A = 5 meters squared.
Answer:
x = 10
Step-by-step explanation:
![x - 7 = 13 - x](https://tex.z-dn.net/?f=x%20-%207%20%3D%2013%20-%20x)
Step 1 : Collect like terms and simplify
![x + x = 13 + 7 \\ 2x = 20](https://tex.z-dn.net/?f=x%20%2B%20x%20%3D%2013%20%2B%207%20%5C%5C%202x%20%3D%2020)
Step 2 : Divide both sides of the equation by 2
![\frac{2x}{2} = \frac{20}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2x%7D%7B2%7D%20%20%3D%20%20%5Cfrac%7B20%7D%7B2%7D%20)
Step 3 : Simplify by cross cancellation of common term : 2
![x = 10](https://tex.z-dn.net/?f=x%20%3D%2010)
Answer:
x= 13/22
Step-by-step explanation:
you can substitute y= 34 x on the second equation
34x = -54x +52 add 54x to both sides
34x +54x = -54x +54x +52
88x = 52 divide both side by 4
22x = 13 divide both sides by 22
x= 13/22
Answer:
The first and second iteration of Newton's Method are 3 and
.
Step-by-step explanation:
The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form
based on the following formula:
![x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}](https://tex.z-dn.net/?f=x_%7Bi%2B1%7D%20%3D%20x_%7Bi%7D%20-%5Cfrac%7Bf%28x_%7Bi%7D%29%7D%7Bf%27%28x_%7Bi%7D%29%7D)
Where:
- i-th Approximation, dimensionless.
- (i+1)-th Approximation, dimensionless.
- Function evaluated at i-th Approximation, dimensionless.
- First derivative evaluated at (i+1)-th Approximation, dimensionless.
Let be
and
, the resultant expression is:
![x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}](https://tex.z-dn.net/?f=x_%7Bi%2B1%7D%20%3D%20x_%7Bi%7D%20-%5Cfrac%7Bx_%7Bi%7D%5E%7B2%7D-8%7D%7B2%5Ccdot%20x_%7Bi%7D%7D)
First iteration: (
)
![x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}](https://tex.z-dn.net/?f=x_%7B2%7D%20%3D%202-%5Cfrac%7B2%5E%7B2%7D-8%7D%7B2%5Ccdot%20%282%29%7D)
![x_{2} = 2 + \frac{4}{4}](https://tex.z-dn.net/?f=x_%7B2%7D%20%3D%202%20%2B%20%5Cfrac%7B4%7D%7B4%7D)
![x_{2} = 3](https://tex.z-dn.net/?f=x_%7B2%7D%20%3D%203)
Second iteration: (
)
![x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}](https://tex.z-dn.net/?f=x_%7B3%7D%20%3D%203-%5Cfrac%7B3%5E%7B2%7D-8%7D%7B2%5Ccdot%20%283%29%7D)
![x_{3} = 2 - \frac{1}{6}](https://tex.z-dn.net/?f=x_%7B3%7D%20%3D%202%20-%20%5Cfrac%7B1%7D%7B6%7D)
![x_{3} = \frac{11}{6}](https://tex.z-dn.net/?f=x_%7B3%7D%20%3D%20%5Cfrac%7B11%7D%7B6%7D)
Answer:
For college, a minimum 75 hours are required in the US.
Step-by-step explanation:
I googled it.