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bonufazy [111]
3 years ago
11

The cost of a large flat screen tv is decreasing 20% per year.

Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0
Let x be the old price

X= 1200$
The price decreased 20% after 1 year to become price y :
Y= 0.8x
= 0.8 (1200)
= 960$
In the year after y also decreased 20% to be price y’:
Y’= 0.8y
= 0.8 (960)
= 768 $
The price y’ then decreased 20% to become price y’’:
Y’’ = 0.8 y’
= 0.8 (768)
= 614.4 $
Then the price will be 614.4 $ after 3 years
Dimas [21]3 years ago
8 0

Answer:

614.4$

Step-by-step explanation:

We know that every year, the value depreciates 20%. Thus, the new value at the end of each year is equal to 80% of the old value. As a result, the value in 3 years is equal to multiplying the original value (1200) by 80% 3 times. As 80%=0.8, 1200*(0.8)^3=614.4 is our answer

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Step-by-step explanation:

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Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

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= \cot^{6} x

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= \cot^{4}x [\csc^{2}x - 1]  

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= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

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= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

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= \cos^{3} x\sin^{2} x

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{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

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= \sin^{4}x - \cos^{4}x

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{Since \sin^{2}x + \cos^{2} x = 1}

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= 1 - 2\cos^{2}x + 2 \cos^{4} x

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