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3 years ago

The cost of a large flat screen tv is decreasing 20% per year.

2 answers:

8 0

Let x be the old price

X= 1200$
The price decreased 20% after 1 year to become price y :
Y= 0.8x
= 0.8 (1200)
= 960$
In the year after y also decreased 20% to be price y’:
Y’= 0.8y
= 0.8 (960)
= 768 $
The price y’ then decreased 20% to become price y’’:
Y’’ = 0.8 y’
= 0.8 (768)
= 614.4 $
Then the price will be 614.4 $ after 3 years

Dimas [21]3 years ago

8 0

Answer:

614.4$

Step-by-step explanation:

We know that every year, the value depreciates 20%. Thus, the new value at the end of each year is equal to 80% of the old value. As a result, the value in 3 years is equal to multiplying the original value (1200) by 80% 3 times. As 80%=0.8, 1200*(0.8)^3=614.4 is our answer

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Find m(angle) ABC 21 132 48 19

Brut [27]

I don't like these algebra problems which pretend to be geometry.

These are supplementary angles adding to 180 degrees; geometry done.

7x - 1 + 3x - 9 = 180

10 x = 190

x = 19

ABC=3x - 9 = 3(19) - 9 = 48

Answer 48°

5 0

2 years ago

Read 2 more answers

Will someone please answer this and remind me how to solve this

Veseljchak [2.6K]

Answer:

Step-by-step explanation:

Since the two triangles are similar, you can use proportions to solve for the value of $x$

$\frac{x}{12} = \frac{4}{3}$

Now, just multiply 4 and 12.

$4 * 12 = 48$

Then divide that by 3.

$48 / 3 = 16$

Therefore, $x = 16$ .

5 0

3 years ago

Read 2 more answers

- Which is greater? 5 2 a) or 16 9

azamat

Answer:

5/2

Step-by-step explanation:

5/2= 2 1/2

while 16/9=1 7/9

6 0

3 years ago

Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the trian

Alla [95]

Answer: mass (m) = 4 kg

center of mass coordinate: (15.75,4.5)

Step-by-step explanation: As a surface, a lamina has 2 dimensions (x,y) and a density function.

The region D is shown in the attachment.

From the image of the triangle, lamina is limited at x-axis: 0≤x≤2

At y-axis, it is limited by the lines formed between (0,0) and (2,1) and (2,1) and (0.3):

Points (0,0) and (2,1):

y = $\frac{1-0}{2-0}(x-0)$

y = $\frac{x}{2}$

Points (2,1) and (0,3):

y = $\frac{3-1}{0-2}(x-0) + 3$

y = -x + 3

Now, find total mass, which is given by the formula:

$m = \int\limits^a_b {\int\limits^a_b {\rho(x,y)} \, dA }$

Calculating for the limits above:

$m = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2(x+y)} \, dy \, dx }$

where a = -x+3

$m = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {(xy+\frac{y^{2}}{2} )} \, dx }$

$m = 2.\int\limits^2_0 {(-x^{2}-\frac{x^{2}}{2}+3x )} \, dx }$

$m = 2.\int\limits^2_0 {(\frac{-3x^{2}}{2}+3x)} \, dx }$

$m = 2.(\frac{-3.2^{2}}{2}+3.2-0)$

m = 2(-4+6)

m = 4

Mass of the lamina that occupies region D is 4.

Center of mass is the point of gravity of an object if it is in an uniform gravitational field. For the lamina, or any other 2 dimensional object, center of mass is calculated by:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$