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sashaice [31]
3 years ago
6

On the rectangular coordinate system, what is the shortest distance between points (−4, 3) and (−2, −1)?

Mathematics
2 answers:
erastova [34]3 years ago
4 0

Answer:

In other words to what the dude above me said, the answer is "a''

Step-by-step explanation:

pogonyaev3 years ago
3 0
Shortest Distance = \sqrt{ (-4+2)^{2} + (3+1)^{2} }
Shortest Distance = \sqrt{ (-2)^{2} + (4)^{2} }
Shortest Distance = \sqrt{20}
Shortest Distance = 4.47 units
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After recording the pizza delivery times for two different pizza shops you conclude one pizza shop has a mean delivery of 45 min
In-s [12.5K]

Answer:

C

Step-by-step explanation:

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6 0
4 years ago
A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an
chubhunter [2.5K]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

                                                                            Predicted value

                           Active value                 Fraudulent       Non-fraudulent

                              Fraudlent                         30                       58

                          non-fraudulent                   32                     920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of \left( {b + c} \right)(b+c) and the total number of records.

The classification matrix is, shown above

The total number of records is, 30 + 58 + 32 + 920 = 1,040

The error rate is,

\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}  

The percentage is 0.0865 \times 100 = 8.65

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and \left( {a + b} \right)(a+b) .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}  

The percentage is, 0.6591 \times 100 = 65.91

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and \left( {c + d} \right)(c+d) .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}

The percentage is, 0.9664 \times 100 = 96.64

8 0
3 years ago
Since there are 12 tenths you need to regroup. you can regroup 12 tenths as 1 whole and 2 tenths
Effectus [21]
1 whole, 1 tenth, 10 ones = 12 tenths
6 0
3 years ago
George is painting fences at the zoo. It takes 2 2/3 cans of paint to paint each fence. If George paints 9 fences, how much pain
sergij07 [2.7K]

Answer: 24 cans

Step-by-step explanation:

Given

George has 9 fence

It requires 2\frac{2}{3} cans to paint a fence

So, 9 fence required

\Rightarrow 9\times 2\dfrac{2}{3}\\\\\Rightarrow 9\times \dfrac{8}{3}\\\\\Rightarrow 3\times 8=24\ \text{cans}

9 fence requires 24 cans

4 0
3 years ago
A miner descended 1200 feet into a mine. While in the mine, he then rose 450 feet and then descended 150 feet. What was the mine
Dovator [93]
The net loss is 1150
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