After h hours, she will have traveled: 70h miles
Answer:
<em>The distance from the point to the line is approximately 3.2 units</em>
Step-by-step explanation:
<u>Distance From a Point to a Line</u>
Is the shortest distance from a given point to any point on an infinite straight line. The shortest distance occurs when the segment from the point and the line are perpendiculars.
If the line is given by the equation ax + by + c = 0, where a, b and c are real constants, the distance from the line to a point (x0,y0) is
The line is given by the equation:
y=3x. We need to transform it into the specified form.
Subtracting 3x:
y - 3x = 0
Comparing with the general form of the line, we have
a=-3, b=1, c=0
The point (xo,yo) is (-1,7), thus:
The distance from the point to the line is approximately 3.2 units
Answer:
z would equal 20°
Step-by-step explanation:
This means ACB and EFD are 2 similar triangles
They have the same shape but different size
In ACB because 3 corner of a traingle must = 180° so in this case, corner BAC would = 180 - 65 - 55 = 60°
As you can see, BC is 3 times as large as DF, this means triangle ACB is larger than triangle EFD 3 times, this would lead to corner BAC is larger than corner DEF 3 times.
Corner DEF would = corner BAC / 3
= 60° / 3
= 20°
SO z would equal 20°
Hope this helped :3
we are asked in the problem to simplify the expression (1/64) ^ -2/3 * 25 ^ -3/3. In this case, the first step is to separately determine the values of (1/64) ^ -2/3 and 25 ^ -3/3 and then multiply the values. This is equal to 16 * 1/25 equal to 16/25.
Surface area of the prism= surface area of the base + surface area of the two triangles + surface area of the two rectangles.
Surface area of the base=(3 yd * 7 yd)=21 yd².
Surface area of the two triangles=2*(3 yd * 4 yd)/2=12 yd².
Surface area of the two rectangles=(7 yd * 5 yd) + (7 yd * 4yd)=35 yd² + 28 yd²=
=63 yd²
Surface of the prism=21 yd² + 12 yd² + 63 yd²=96 yd²
Remember:
surface area of a triangle=(base * height)/2
surface area of a rectangle=base * height.
Answer: C.96 yd²
