Since the rate of descent is a constant this is a linear equation and can be expressed as:
h=vt+b, where h=feet, v=slope or rate, b=y-intercept (y value when x=0 which is the initial height)
h=-2t+b, using the point (3,67) we can solve for b, or the initial height
67=-2(3)+b
67=-6+b
73=b so the initial height was 73 ft and the height equation is then:
h(t)=67-2t so when t=8 you have:
h(8)=67-2(8)
h(8)=67-16
h(8)=51 ft
Answer: n = -9 x2 = -1
Step-by-step explanation:
i might be wrong idk that what i got for my answer
Answer:
May or may not be right, your welcome.
Step-by-step explanation:
Rise/Run.
Plot 1.
Go down 2.
Go to the right 3, plot.
Log w (x^2-6)^4
Using log a b = log a + log b, with a=w and b=(x^-6)^4:
log w (x^2-6)^4 = log w + log (x^2-6)^4
Using in the second term log a^b = b log a, with a=x^2-6 and b=4
log w (x^2-6)^4 = log w + log (x^2-6)^4 = log w + 4 log (x^2-6)
Then, the answer is:
log w (x^2-6)^4 = log w + 4 log (x^2-6)
Answer:
Step-by-step explanation:
A)
<u>According to dimensions of the garage, the scale is:</u>
- 1 in : 20 ft, as the width of the garage is 20 ft and on paper is 1 in
B)
Living room
<u>Dimensions on paper: </u>
C)
<u>Actual dimensions: </u>
- 2*20 ft = 40 ft and
- 1 1/4 * 20 ft = 25 ft
D)
<u>The area of the living room:</u>
- A = lw = 25*40 = 1000 ft²
<u>Cost of carpet:</u>