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sashaice [31]
3 years ago
7

The population of a town is 2100 and increasing at a rate of 1.3% per year, while the number of cats in the town is currently 10

00 and increasing at a rate of 8% per year. Assuming this trend continues, estimate when the cat population will exceed the human population in this town.
Mathematics
1 answer:
stich3 [128]3 years ago
6 0

Answer:

when # cats exceeds 2,313

Step-by-step explanation:

if you graph y = .013x + 2100 and y = .08 + 1000 you will see the lines intersect when the town population is 16,418 and the number of cats equals 2,313.

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Answer:

Of the 16 possible experimental outcomes, 4 outcomes result in exactly 1 success.

The probability of a determined sample point with an outcome of one success is P=0.0992.

Step-by-step explanation:

We have a proportion of success (the selection of a manager who reads e-mail in the bathroom) of p=0.18.

The sample size is n=4.

We can model this as a binomial random variable.

The sample space is [0, 1, 2, 3, 4].

The possible outcomes for x=0 (that is no manager in the sample reads email in the bathroom) can be calculated as:

C(0)=\dbinom{4}{0}=\dfrac{4!}{4!0!}=1

The same way we can calculate all the other possible outcomes:

C(1)=\dbinom{4}{1}=\dfrac{4!}{3!1!}=\dfrac{4}{1}=4\\\\\\C(2)=\dbinom{4}{2}=\dfrac{4!}{2!2!}=\dfrac{4*3}{2*2}=6\\\\\\C(3)=\dbinom{4}{3}=\dfrac{4!}{3!1!}=4\\\\\\C(4)=\dbinom{4}{4}=\dfrac{4!}{4!0!}=1

The sum of this outcomes is 16 possible outcomes. Of the 16 possible experimental outcomes, 4 outcomes result in exactly 1 success.

The probability of an outcome with 1 success is the product of p (the one that reads email) times (1-p)^3 (the other 3 that do not read emails in the bathroom):

p\cdot (1-p)^3=0.18\cdot0.82^3=0.18\cdot 0.5514=0.0992

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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