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MatroZZZ [7]
3 years ago
6

How do I write Domain of an inequality

Mathematics
1 answer:
Katen [24]3 years ago
4 0

Answer:As an inequality, we would write Read as "the domain of the function is all values of x which are greater than or equal to zero". For more on inequalities see Inequalities. In so-called interval notation, the same function has a domain of This describes the set of values from 0 to positive infinity.

Step-by-step explanation:

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GIVE ME BRAINLIEST AND ILL GIVE U ANSWER

Step-by-step explanation:

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On a bus, 2 adults can ride for the same price as 3 children. If 1 adult ticket costs $48, what is the price of a child's ticket
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Pleas help it’s due tomrrow
katovenus [111]

Answer:

Step-by-step explanation:

K is located at -25

L is located at -15

just move 5 units away from J on both sides

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5 0
3 years ago
The manager of an accounting department wants to form a two
Y_Kistochka [10]

Answer: 153

Step-by-step explanation:

When we have a group of N elements, the total number of combinations of K elements ( K ≤ N) is:

C (N, K) = \frac{N!}{(N-k)!*K!}

Where N! = N*(N - 1)*(N - 2)*...*2*1

In this case, we have a group of 18 people (then N = 18) and we want to see how many different combinations of 2 we can make (K = 2).

Using the above equation we get:

C(18, 2) = \frac{18!}{(18 - 2)!*2!}  = \frac{18!}{16!*2!} = \frac{18*17}{2}  = 9*17 = 153

There are 153 different ways in which the manager can do this.

5 0
3 years ago
Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of the survey asked respondents to
erastova [34]

Answer:

(a) The probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.

(b) The probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.

Step-by-step explanation:

Let's denote the events as follows:

<em>A</em> = Fell short of expectations

<em>B</em> = Met expectations

<em>C</em> = Surpassed expectations

<em>N</em> = no response

<u>Given:</u>

P (N) = 0.04

P (A) = 0.26

P (B) = 0.65

(a)

Compute the probability that a randomly selected alumnus would say their experience surpassed expectations as follows:

P(C) = 1 - [P(A) + P(B) + P(N)]\\= 1 - [0.26 + 0.65 + 0.04]\\= 1 - 0.95\\= 0.05

Thus, the probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.

(b)

The response of all individuals are independent.

Compute the probability that a randomly selected alumnus would say their experience met or surpassed expectations as follows:

P(B\cup C) = P(B)+P(C)-P(B\cap C)\\=P(B)+P(C)-P(B)\times P(C)\\= 0.65 + 0.05 - (0.65\times0.05)\\=0.6675\\\approx0.67

Thus, the probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.

5 0
4 years ago
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