I hope this is right, but I think it should take a remaining six hours for the new guy to fix your car. He worked on it for two hours with the other mechanic, but it still takes him 8 hours total to fix the car. So he still has six more hours to fix your car. Again, I hope this is right.
Answer: 12 students
Step-by-step explanation:
Let X and Y stand for the number of students in each respective class.
We know:
X/Y = 2/5, and
Y = X+24
We want to find the number of students, x, that when transferred from Y to X, will make the classes equal in size. We can express this as:
(Y-x)/(X+x) = 1
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We can rearrange X/Y = 2/5 to:
X = 2Y/5
The use this value of X in the second equation:
Y = X+24
Y =2Y/5+24
5Y = 2Y + 120
3Y = 120
Y = 40
Since Y = X+24
40 = X + 24
X = 16
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Now we want x, the number of students transferring from Class Y to Class X, to be a value such that X = Y:
(Y-x)=(X+x)
(40-x)=(16+x)
24 = 2x
x = 12
12 students must transfer to the more difficult, very early morning, class.
The middle point of BC is (0,2), the midpoint of CD is (1,0)
to prove two lines are parallel, prove their slopes are the same.
slope of BD: m=rise/run=4/-2=-2 (the run is negative because to get to B from D on the grid, you have to move from right to left, then upward. If the horizontal move is from left to right, the run is positive)
slope of EG: m=rise/run=2/-1=-2
EG and BD have the same slope, so they are parallel.
Answer:
42°
Step-by-step explanation:
Since all the angles in the figure add up to 180°...
180 - 54 = 126
3x = 126°
x = 126 ÷ 3 = 42
If the student received marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade is 81.2 percent.
<h3>What is mean?</h3>
The mean is described as a single number that indicates either the closed value for each item in the collection of data or the mean value for the whole set of data.
On her four regular tests, a student had grades of 84, 78, 84, and 72 out of 100. She received 86 percent on her class projects and 78 percent on the final test.
You may compute the weighted mean as follows:
Hence, if the student had marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade would be 81.2 percent.
To learn more about the mean refer;
brainly.com/question/22871228
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