Answer:
See proof below
Step-by-step explanation:
Two triangles are said to be congruent if one of the 4 following rules is valid
- The three sides are equal
- The three angles are equal
- Two angles are the same and a corresponding side is the same
- Two sides are equal and the angle between the two sides is equal
Let's consider the two triangles ΔABC and ΔAED.
ΔABC sides are AB, BC and AC
ΔAED sides are AD, AE and ED
We have AE = AC and EB = CD
So AE + EB = AC + CD
But AE + EB = AB and AC+CD = AD
We have
AB of ΔABC = AD of ΔAED
AC of ΔABC = AE of ΔAED
Thus two sides the these two triangles. In order to prove that the triangles are congruent by rule 4, we have to prove that the angle between the sides is also equal. We see that the common angle is ∡BAC = ∡EAC
So triangles ΔABC and ΔAED are congruent
That means all 3 sides of these triangles are equal as well as all the angles
Since BC is the third side of ΔABC and ED the third side of ΔAED, it follows that
BC = ED Proved
It’s 56 degrees. All the outside values equal 360 so you make them equal to that to solve for x and you get x=18. Then you solve for C and get 124. Then subtract 180-124 for DCE and you get 56
I think they have no points in common because A or B aren't part of CD. AC would share a point with CD. The point they would share is C. THE ANSWER IS B.
Its 12, becuse if its a Circle then you can look at it the same way you look at a clock which has 12 numbers on it and 4 and 11 are directly across each other.
Answer:
I think the answer is (8,2)
