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Ronch [10]
3 years ago
7

-8(-5+4x)=104 sssssssssssssssssssssssssssssssssssssssss

Mathematics
2 answers:
vodomira [7]3 years ago
5 0

Answer:

Step-by-step explanation:

-8(-5+4x)=104

40-32x=104

-104.      -104

-64-32x=0

Factorise

-32(x+2)

x=2

astra-53 [7]3 years ago
3 0

Answer:

what is the meaning of 'sssssssssssssssssssssssss'

the answer is x=2

first work out -8(-5+4x) u will get 40+32x

40+32x=104 then group the like terms together.

it will become 32x=104-40. =32x=64

then divide both sides by 32 ur final answer is

x =2

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Step-by-step explanation:

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Natasha_Volkova [10]

Answer:

Part A) x=(+/-)\frac{3\sqrt{3}}{2}

Part B) x=2.5  and x=-0.5

Part C) x=-1  and x=3

Part D) x=\frac{9+\sqrt{193}}{8}  and x=\frac{9-\sqrt{193}}{8}

Step-by-step explanation:

Part A) we have

4x^{2}-27=0          

we know that      

The <u><em>square root property</em></u> states that if we have an equation with a perfect square on one side and a number on the other side, then we can take the square root of both sides and add a plus or minus sign to the side with the number and solve the equation.

isolate the term that contains the squared variable

4x^{2}=27            

x^{2} =\frac{27}{4}

take the square root of both sides

x=(+/-)\frac{\sqrt{27}}{2}

simplify

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Part B) we have

4x^{2}-8x-5=0    

Using the quadratic equation  

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0 is  

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

4x^{2}-8x-5=0  

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a=4\\b=-8\\c=-5

substitute in the formula

x=\frac{-(-8)(+/-)\sqrt{-8^{2}-4(4)(-5)}} {2(4)}

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x=\frac{8(+/-)12}{8}

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x=\frac{8(-)12}{8}=-0.5

Part C) we have

4x^{2}-8x-12=0    

Using Factoring  

Simplify the expression first

Divide by 4 both sides

x^{2}-2x-3=0  

Find two numbers a and  b such that

a+b=-2

ab=-3

Solve the system by graphing

The solution is a=1, b=-3  

see the attached figure

so

4x^{2}-8x-12=4(x-1)(x+3)  

The solutions are

x=1, x=-3

Part D) we have

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Group terms that contain the same variable, and move the constant to the opposite side of the equation

4x^{2}-9x=7

Factor the leading coefficient

4(x^{2}-\frac{9}{4}x)=7

Complete the square. Remember to balance the equation by adding the same constants to each side

4(x^{2}-\frac{9}{4}x+\frac{81}{64})=7+\frac{81}{16}

4(x^{2}-\frac{9}{4}x+\frac{81}{64})=\frac{193}{16}

Rewrite as perfect squares

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x=\frac{9+\sqrt{193}}{8}

x=\frac{9-\sqrt{193}}{8}

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