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2 years ago

What is the solution of the system of equations? Show your work.

Mathematics

1 answer:

scZoUnD [109]2 years ago

3 0

Answer:

1.Solve for y in 2x+y=-3

y=-3-2x

2. Substitute y= -3 - 2x into 4x-2y=10

8x+6=10

3 Solve for x in 8x+6=10

x=1/2

4. Substitute x=1/2 into y = - 3 - 2x

y= -4

5. So you get...,

x=1/2

y=−4

Step-by-step explanation:

you're welcome :)

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1/6 + 2/3 tell me wat it is pls

Nutka1998 [239]

Answer: 5/6

Step-by-step explanation:

2/3=4/6

1/6 + 4/6 = 5/6

5 0

3 years ago

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about 30% of the population is left-handed. If two people are random selected what is the probability that both are left handed?

Svetradugi [14.3K]

Answer:

0.91

Step-by-step explanation:

1 - P(both left handed)

1 - 0.3² = 0.91

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3 years ago

V=ZQT Solve for z in this equation

Ganezh [65]

Answer:

Z= V/QT

Step-by-step explanation:

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2 years ago

The probability that Josslyn is on time for a given class is 99 percent. If there are 32 classes during the semester, what is th

Gre4nikov [31]

Answer:

The best estimate is 32 out of 32 times, she will be early to class

Step-by-step explanation:

The probability of being early is 99% = 99/100 = 0.99

So out of 32 classes, the best estimate for the number of times she will be early to class will be;

0.99 * 32 = 31.68

To the nearest integer = 32

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2 years ago

A marketing firm is asked to estimate the percent of existing customers who would purchase a "digital upgrade" to their basic ca

Ugo [173]

Answer: A. 664

Step-by-step explanation:

Given : A marketing firm is asked to estimate the percent of existing customers who would purchase a "digital upgrade" to their basic cable TV service.

But there is no information regarding the population proportion is mentioned.

Formula to find the samples size , if the prior estimate to the population proportion is unknown :

$n=0.25(\dfrac{z*}{E})^2$

, where E = Margin of error.

z* = Two -tailed critical z-value

We know that critical value for 99% confidence interval = $z*=2.576$ [By z-table]

Margin of error = 0.05

Then, the minimum sample size would become :

$n=0.25(\dfrac{2.576}{0.05})^2$

Simplify,

$n=0.25\times2654.3104=663.5776\approx664$

Thus, the required sample size= 664

Hence, the correct answer is A. 664.

5 0

3 years ago