Use the cross product to find the orthogonal vector, solve the parametric equation to see at which (t) the point + orthogonal vector intersects the plane, the distance is (t) * norm of vector

3 0

2 years ago

The width of a rectangle measures (2.5u+9.8)(2.5u+9.8) centimeters, and its length measures (1.5u+3.9)(1.5u+3.9) centimeters. Wh

icang [17]

Solution,

We have,

Width of rectangle, b = (2.5u+9.8) cm

Length of rectangle, l = (1.5u+3.9) cm

We need to find the expression for the perimeter of the rectangle. The formula for the perimeter of a rectangle is given by:

Perimeter = 2(l+b)

P = 2[(2.5u+9.8)+(1.5u+3.9)]

Collecting like terms

P = 2[(2.5u+1.5u)+(9.8+3.9)]

P=2(4u+13.7)

⇒ P = 8u+27.4

So, the expression for the perimeter of the rectangle is (8u+27.4) cm.

3 0

2 years ago