Answer:67
Step-by-step explanation:
Answer:
Step-by-step explanation:
On the day of the canteen, 800 coupons were sold, the price of each coupon was RM 30 and RM 50 respectively. The amount of money earned from the sale of coupons was RM30000. How many copies of RM30 and RM50 coupons were sold?
Let:
RM 30 = x
RM 50 = y
x + y = 800 - - - (1)
30x + 50y = 30000 - - - (2)
From (1)
x = 800 - y
Put x = 800 - y in (2)
30(800 - y) + 50y = 30000
24000 - 30y + 50y = 30000
24000 + 20y = 30000
20y = 30000 - 24000
20y = 6000
y =
Answer:
A= B= C= D= E= F=
Step-by-step explanation:
Answer:
There isnt even a graph shown to graph on.
Answer:
a) 0.3246
b) 0.0043
Step-by-step explanation:
- For player 1 ; Probability of winning = P(W) = 1/3
- Probability of loosing; P(winning) + P( Loosing) = 1
a) To find Find P(N <= 10) = P(2)+P(3)+P(4)+P(5)+P(6)+P(7)+P(8)+P(9)+P(10)
= (1/3)^2 + (1/3)^2 x 2/3 + (1/3)^2 x (2/3)^2 + (1/3)^2x (2/3)^3 + (1/3)^2 x (2/3)^4
X (1/3)^2 x (2/3)^5 + (1/3)^2 x (2/3)^6 + (1/3)^2 x (2/3)^7 + (1/3)^2 x (2/3)^8
= 0.3246
b) Find P(N = 10) = (1/3)^2 x (2/3)^8 = 0.0043
