A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.
B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4.
(13−10)! 3!
C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =
10! 3!
9!1! 1!2!
10! 3!
8!2! 2!1!
10! 3!
7!3! 3!0!
= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =
= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =
= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285
1·2·3
<span>possible choices.</span><span>
</span>
Answer:
EBC = 90
FBG = 25
ABF = 115
ABG = 140
EBG = 50
<u>H</u><u>o</u><u>p</u><u>e</u><u> </u><u>t</u><u>h</u><u>a</u><u>t</u><u> </u><u>h</u><u>e</u><u>l</u><u>p</u><u>e</u><u>d</u><u> </u><u>:</u><u>)</u>
Answer:
37.7 yd
Step-by-step explanation:
The circumference of a circle can be found using the formula ...
C = 2πr
For a radius of 6 yd, the circumference is ...
C = 2π(6 yd) = 12π yd ≈ 37.7 yd
The length of the circular border was 37.7 yards.
Answer:
y= 35
Step-by-step explanation:
y directly proportional to x
where x= 2, y= 10
y=kx
10= k× 2
k= 10/2
k= 5
to find y when x is 7
y = kx
y = 5× 7
y= 35
