Answer:
the answer to your question is C
Step-by-step explanation:
The speed of the faster cyclist will be 30 miles/hour.
<em><u>Explanation</u></em>
One cyclist is 3 times as fast as the other.
Lets assume that the speed of the slower cyclist is
miles/hour.
So, the <u>speed of the faster cyclist</u> will be:
miles/hour.
They start riding toward each other at the same time and meet 2 hours later.
We know that, 
So, the <u>distance traveled by slower cyclist</u> in 2 hours
miles and the <u>distance traveled by faster cyclist</u>
miles.
Given that, they were 80 miles apart at the starting. So, the equation will be.....

So, the speed of the faster cyclist will be: (3×10)= 30 miles/hour.
Driving 70 miles per hour.
Slow your speed means decrease in speed= 70+(-15)=70-15=55 miles/ hr
And then return to speed of 70 miles/hr means add 15 miles to the speed.
We get
70+(-15)+15 =70 miles / hr
Option D is correct.
The second choice for the first problem and the third choice for the second problem
A. Y=1/2x + 2
Y=1/2 times 2 + 2 = 3
Y=1/2 times 4 + 2 = 4
Y=1/2 times 6 + 2 = 5
Y=1/2 times 8 + 2 = 6