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3 years ago

Tell whether the triangle with the given side lengths is a right triangle.

Mathematics

1 answer:

Sidana [21]3 years ago

7 0

Answer:

Step-by-step explanation:

7²+24²=49+576=625=25²≠26²

You might be interested in

What is greater than 40 but less than 20

Paladinen [302]

I've already been complemented twice on my previous answer, but then I discovered that I mis-read the question. My entire original answer was wrong, and I have to delete it.

I don't believe that any number can satisfy both of those conditions.
I'll say the question has no answer.

3 0

3 years ago

Which pair of angles is an example of supplementary angles?

artcher [175]

Answer:

A. Angle 1 and Angle 7

Step-by-step explanation:

Those two are the only angles that when added up, the sum is 180.

Angle 7 and Angle 2 are also congruent, so if Angle two forms a straight line with Angle 1, Angle 7 should be able to do that too.

6 0

2 years ago

Which ordered pairs are in the solution set of the system of linear inequalities? y > Negative one-thirdx + 2 y < 2x + 3

Natasha2012 [34]

Answer:

Option ( A ) is the answer at (2, 2), (3, 1), (4, 2)

Step-by-step explanation:

3 0

3 years ago

For which function is f(x) equal to f^1(x) ( answer choices in picture )

Sonja [21]

Answer:

C. $f(x)=\frac{x+1}{x-1}$

Step-by-step explanation:

Let's find the inverse of each of the given options.

Option A:

$f(x)=\frac{x+6}{x-6}\\y=\frac{x+6}{x-6}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+6}{y-6}$

Rewrite in terms of 'y'. This gives,

$x(y-6)=y+6\\xy-6x=y+6\\xy-y=6x+6\\y=\frac{6x+6}{x-1}$

The given function $y=\frac{6x+6}{x-1}\ne y=\frac{x+6}{x-6}$

So, option A is incorrect.

Option B:

$f(x)=\frac{x+2}{x-2}\\y=\frac{x+2}{x-2}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+2}{y-2}$

Rewrite in terms of 'y'. This gives,

$x(y-2)=y+2\\xy-2x=y+2\\xy-y=2x+2\\y=\frac{2x+2}{x-1}$

The given function $y=\frac{2x+2}{x-1}\ne y=\frac{x+2}{x-2}$

So, option B is incorrect.

Option C:

$f(x)=\frac{x+1}{x-1}\\y=\frac{x+1}{x-1}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+1}{y-1}$

Rewrite in terms of 'y'. This gives,

$x(y-1)=y+1\\xy-x=y+1\\xy-y=x+1\\y=\frac{x+1}{x-1}$

The given function $y=\frac{x+1}{x-1}\ equals\ y=\frac{x+1}{x-1}$

So, option C is correct.

Option D:

$f(x)=\frac{x+5}{x-5}\\y=\frac{x+5}{x-5}$

To find $f^{-1}(x)$ , replace 'x' with 'y' and 'y' with 'x'. This gives,

$x=\frac{y+5}{y-5}$

Rewrite in terms of 'y'. This gives,

$x(y-5)=y+5\\xy-5x=y+5\\xy-y=5x+5\\y=\frac{5x+5}{x-1}$

The given function $y=\frac{5x+5}{x-1}\ne y=\frac{x+6}{x-6}$

So, option D is incorrect.

Therefore, only option C is correct.

7 0

3 years ago

Slove for P. 5/7=p+4/7

Sever21 [200]

p= 1/7
Alright, so first, you need to flip the equation.It will turn into p+4/7=5/7
Next, you want to get the variable by itself so you need to subtract 4/7 from both sides. 5/7-4/7=1/7
p=1/7

5 0

3 years ago