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3 years ago

7

Formula for finding side length of a cube

1 answer:

Maksim231197 [3]3 years ago

7 0

Answer:

cube root of volume

Step-by-step explanation:

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WILL MARK BRAINLIEST. Can someone help me wit des 2 questions?

Mnenie [13.5K]

Answer:

Zero is a number that can be equal to its opposite.

So, the given equation has solution for which LHS=RHS=0.

Step-by-step explanation:

The answer to the equation is 2

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3 years ago

If apples cost $1.08 per pound, how much would 3.8 pounds cost?

DENIUS [597]

Answer:

4.10

Step-by-step explanation:

1.08 * 3.8 = 4.104

but money is 2dp so...

4.10

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2 years ago

ammar hikes 23/4 miles of nature trail in 1 hour and 15 min .How many miles of trail does ammar hike per hour? pleas help me to

telo118 [61]

23/4 miles is as much as 5 3/4 miles. We can also write it as a decimal, because 5 3/4 = 5,75 miles.

If Ammar hikes 5,75 miles in 1 1/4 hour, then we need to find out what distance does he hike in 1/4 hour (15 minutes). To do that we can just divide 5,75 by 5 (because dividing 1 1/4 by 5 will give us 1/4 we're looking for).

5,75 / 5 = 1,15

It means that in one hour Ammar hikes 5,75 - 1,15 = 4,6 miles.

We can also write it as a fraction:

4,6 = 4 6/10 = 4 3/5 = 23/5 miles

Just pick whichever form you like :)

3 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

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3 years ago

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During a thunderstorm, 600 millimeters of rain fell in 30 minutes. How fast did the rain fall, in millimeters per minute?

madreJ [45]

20 milliliters per minute

5 0

3 years ago

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