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2 years ago

Compare the two numbers by choosing <, >or =

Mathematics

1 answer:

vlabodo [156]2 years ago

4 0

Answer:

In order to compare the fractions we can first obtain the LCM of the denominators of the two fractions and that is to say

= LCM of 5 and 3 which is 15

= $\frac{2}{5} * 15$

and also:

= $\frac{1}{3} * 15$

So in conclusion the numbers 6 and 5 will determine the sign to be used and since 6 is for $\frac{2}{5}$ and 5 is for $\frac{1}{3}$ and numerically 6 is greater than 5 therefore:

$\frac{2}{5} > \frac{1}{3}$

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there are 27 children in Ms. kloot's class. when the flu was going around , about 26% of the students in the class were absent.

ValentinkaMS [17]

Answer:

About 8 children were sick

Step-by-step explanation:

The total number of children in Ms. kloot's class is 27.

The percentage of students who were absent due to the flu 26.

Number of children who were sick

$= \frac{26}{100} \times 27$

This simplifies to:

$= 7.02$

Therefore about 8 children were sick

8 0

3 years ago

23 times 4 times 25 times 23 times(25 times 4) times 4 =

Dmitrij [34]

21160000
just multiply every number you see but make sure you multiply the numbers inside the parentheses first

3 0

3 years ago

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Hehehehehehehehheheheh

elena-s [515]

Answer:

E and B

Step-by-step explanation:

5 0

3 years ago

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The diagram below represents the net of a triangular prism. What is the surface area of the triangular prism?

AleksandrR [38]

Answer:

(C)

Step-by-step explanation:

The diagram is divided ninto 5 parts that is rectangles ABCD, CHGD, GFEH and triangles CIH and DGJ.

Area of rectangle ABCD= $l{\times}b$

= $12{\times}6=72cm^{2}$

Area rectangle CDHG= $l{\times}b$

= $12{\times}8=96cm^{2}$

Area rectangle HGFE= $l{\times}b$

= $10{\times}12=120cm^{2}$

Area of triangles CIH and DIG= $2{\times}\frac{1}{2}{\times}b{\times}h$

= $6{\times}8=48cm^{2}$

Surface area of the triangular prism=Area of rectangle ABCD+Area rectangle CDHG+Area rectangle HGFE+Area of triangles CIH and DIG

= $72+96+120+48=336cm^{2}$

Hence, option C is correct.

3 0

3 years ago

Anna, Beth and Colleen are softball players. This season, Anne had 65 base hits in 160 at-bats. Beth batting average was 0.399,

zheka24 [161]

Answer:

Anne is the best hitter as she has the best hitting average of 0.406

Step-by-step explanation:

Anne hits 65 bases out of 160 at - bats.

Beth's betting average = 0.399

Collin's hit = 40%

Now, we need to convert all the three hitting rates into same parameters to compare them with each other.

Average hit rate of Anne = $\frac{\textrm{Total numberof base}}{\textrm{Total number of at - bats}}$

$= \frac{65}{160} = 0.406$

⇒The betting average of Anne = 0.406

Now, The hit - rate of Collin = 40%

Converting the percentage rate into decimal, we get the hit rate of Collin

= $\frac{40}{100} = 0.40$

Hence, we get that Hitting Average of :

<u>Anne = 0.406</u>, Beth = 0.3999 and Collin = 0.400

Hence, from the above data Anne is the best hitter as she has the best hitting average of 0.406.

6 0

3 years ago

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