The transformations which have made to produce the function
y₂ = 1+csc (x-π) from the <span>parent function y = csc x
</span>1. shift up one unit ⇒ shift one unit in the direction of positive y
2. shift to the left equal to π ⇒ shift π units in the direction of positive x
See the attached figure.
Blue graph represents the parent function
Red graph represents the produced function after transformation.
Answer:
1. width = 51 m
2. length = 84 m
Step-by-step explanation:
So remember, the area is (length * width).
It is given that the length is 97, and the area is 4947.
So plug this into a formula:
length * width = area
97 * width = 4947
Solve using inverse operations;
97 * width = 4947
/97 /97
width = 51m
The perimeter of a rectangle can be found by doing, (2 * (length + width)).
The width is given, it is 68m. The perimeter is also given, 304m. So just form an equation using this information:
2 * ( length + width) = perimeter
2 * (length + 68 ) = 304
Distribute;
2 * ( length + 68) = 304
2 length + 136 = 304
Inverse operations;
2length + 136 = 304
-136 -136
2length = 168
/2 /2
length = 84m
Find the unit rate by dividing price by total units:
0.98 / 4 pints = 0.245 per pint
1.46/ 6 pints = 0.243 per pint
The 6 pint size has a lower price per point so it is the better deal.
No, because 2 / 2 is not 3/4
Answer:
Segment JK is a chord in circle H
Line LM is a secant to circle H
Step-by-step explanation:
* Lets revise some definition in the circle
- The radius of the circle is a line segment drawn from the center of
the circle to a point on the circumference of the circle
- The chord of a circle is a line segment whose endpoints lie on the
circumference of the circle
- The secant is a line intersect the circle in two points
- The tangent is a line touch or intersect the circle in one point
* Now lets solve the problem
- In circle H
∵ JK is a segment in circle H
∵ Point J lies on the circumference of circle H
∵ Point K lies on the circumference of circle H
∴ Segment JK is a chord in circle H
∵ LM is a line
∵ LM intersect circle H in two points L and M
∴ Line LM is a secant to circle H
