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Doss [256]
3 years ago
14

Which ordered pairs make both inequalities true? Check all that apply.

Mathematics
2 answers:
Alex17521 [72]3 years ago
8 0

I JUST TOOK THE TEST AND THE ANSWER IS D

olga nikolaevna [1]3 years ago
3 0

Answer:

None of these ordered pairs make both inequalities true.

Step-by-step explanation:

The given inequalities are

y

y>x+1

For (-3,2),

2

The first inequality is not true for (-3,2), therefore option 1 is incorrect.

For (-1,3),

3

The first inequality is not true for (-1,3), therefore option 2 is incorrect.

For (0,2),

2

The first inequality is not true for (0,2), therefore option 3 is incorrect.

For (1,2),

2

2>1+1\Rightarrow 2>2

The second inequality is not true for (1,2), therefore option 4 is incorrect.

For (2,-1),

-1

-1>2+1\Rightarrow -1>3

The second inequality is not true for (2,-1), therefore option 5 is incorrect.

For (2,2),

2

2>2+1\Rightarrow 2>3

The second inequality is not true for (2,2), therefore option 6 is incorrect.

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Answer:

P(M4\ n\ V) = 2.083\%

Step-by-step explanation:

Given

Paper = 20 slips

Word: PENNSYLVANIA

Required

Determine P(Multiple of 4 and V)

The sample size of the 20 slips is:

n(S) = 20

The outcomes of multiples of 4 is:

M4= \{4,8,12,16,20\}

n(M4) = 5

So, the probability of multiples of 4 is:

Pr(M4) = \frac{5}{20}

Pr(M4) = \frac{1}{4}

The sample size of PENNSYLVANIA is:

n(S) = 12

The outcome of V is:

n(V) = 1

So, the probability of V is:

P(V) = \frac{1}{12}

So, the required probability is: P(Multiple of 4 and V)

P(M4\ n\ V) = P(M4) * P(V)

P(M4\ n\ V) = \frac{1}{4} * \frac{1}{12}

P(M4\ n\ V) = \frac{1}{48}

P(M4\ n\ V) = 0.02083

Express as percentage

P(M4\ n\ V) = 0.02083 * 100\%

P(M4\ n\ V) = 2.083\%

4 0
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