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Doss [256]
3 years ago
14

Which ordered pairs make both inequalities true? Check all that apply.

Mathematics
2 answers:
Alex17521 [72]3 years ago
8 0

I JUST TOOK THE TEST AND THE ANSWER IS D

olga nikolaevna [1]3 years ago
3 0

Answer:

None of these ordered pairs make both inequalities true.

Step-by-step explanation:

The given inequalities are

y

y>x+1

For (-3,2),

2

The first inequality is not true for (-3,2), therefore option 1 is incorrect.

For (-1,3),

3

The first inequality is not true for (-1,3), therefore option 2 is incorrect.

For (0,2),

2

The first inequality is not true for (0,2), therefore option 3 is incorrect.

For (1,2),

2

2>1+1\Rightarrow 2>2

The second inequality is not true for (1,2), therefore option 4 is incorrect.

For (2,-1),

-1

-1>2+1\Rightarrow -1>3

The second inequality is not true for (2,-1), therefore option 5 is incorrect.

For (2,2),

2

2>2+1\Rightarrow 2>3

The second inequality is not true for (2,2), therefore option 6 is incorrect.

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Answer:

x = -2, x = 3 − i√8, and x = 3 + i√8

Step-by-step explanation:

g(x) = x³ − 4x² − x + 22

This is a cubic equation, so it must have either 1 or 3 real roots.

Using rational root theorem, we can check if any of those real roots are rational.  Possible rational roots are ±1, ±2, ±11, and ±22.

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g(-11) = 1782

g(11) = 858

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g(22) = 8712

We know -2 is a root.  The other two roots are irrational.  To find them, we must find the other factor of g(x).  We can do this using long division, or we can factor using grouping.

g(x) = x³ − 4x² − 12x + 11x + 22

g(x) = x (x² − 4x − 12) + 11 (x + 2)

g(x) = x (x − 6) (x + 2) + 11 (x + 2)

g(x) = (x (x − 6) + 11) (x + 2)

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Quadratic formula:

x = [ 6 ± √(36 − 4(1)(11)) ] / 2

x = (6 ± 2i√8) / 2

x = 3 ± i√8

The three roots are x = -2, x = 3 − i√8, and x = 3 + i√8.

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Answer:

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