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Doss [256]
3 years ago
14

Which ordered pairs make both inequalities true? Check all that apply.

Mathematics
2 answers:
Alex17521 [72]3 years ago
8 0

I JUST TOOK THE TEST AND THE ANSWER IS D

olga nikolaevna [1]3 years ago
3 0

Answer:

None of these ordered pairs make both inequalities true.

Step-by-step explanation:

The given inequalities are

y

y>x+1

For (-3,2),

2

The first inequality is not true for (-3,2), therefore option 1 is incorrect.

For (-1,3),

3

The first inequality is not true for (-1,3), therefore option 2 is incorrect.

For (0,2),

2

The first inequality is not true for (0,2), therefore option 3 is incorrect.

For (1,2),

2

2>1+1\Rightarrow 2>2

The second inequality is not true for (1,2), therefore option 4 is incorrect.

For (2,-1),

-1

-1>2+1\Rightarrow -1>3

The second inequality is not true for (2,-1), therefore option 5 is incorrect.

For (2,2),

2

2>2+1\Rightarrow 2>3

The second inequality is not true for (2,2), therefore option 6 is incorrect.

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The following is a linear programming formulation of a labor planning problem. There are four overlapping shifts, and management
dexar [7]

Answer:

d. 15

Step-by-step explanation:

Putting the values in the shift 2 function

X1 + X2 ≥ 15

where x1=  13, and x2=2

13+12≥ 15

15≥ 15

At least 15 workers must be assigned to the shift 2.

The LP model questions require that the constraints are satisfied.

The constraint for the shift 2 is that the  number of workers must be equal or greater than 15

This can be solved using other constraint functions e.g

Putting  X4= 0 in

X1 + X4 ≥ 12

gives

X1 ≥ 12

Now Putting the value X1 ≥ 12  in shift 2 constraint

X1 + X2 ≥ 15

12+ 2≥ 15

14 ≥ 15

this does not satisfy the condition so this is wrong.

Now from

X2 + X3 ≥ 16

Putting X3= 14

X2 + 14 ≥ 16

gives

X2  ≥ 2

Putting these in the shift 2

X1 + X2 ≥ 15

13+2 ≥ 15

15 ≥ 15

Which gives the same result as above.

6 0
3 years ago
What adds to get 3 but multiplies to get negative 18
Colt1911 [192]
6 and -3

6 + -3 = 3

6  x -3 = -18

Hope that helps! 
3 0
3 years ago
if you deposit 4500 at 5% annual interest compounded annually how much money will be in the account after 30 months
Alja [10]

Answer:

A = $ 50,978.44

Step-by-step explanation:

First, convert R percent to r a decimal

r = R/100

r = 5%/100

r = 0.05 per year,

Then, solve our equation for A

A = P(1 + r/n)nt

A = 45,000.00(1 + 0.004166667/12)(12)(2.5)

A = $ 50,978.44

8 0
3 years ago
Please ASAP help please !!! Help me anyone
worty [1.4K]

difference of squares means that both the terms are square terms. (also there must be a - symbol)

for example

y^2 - 4

square root of y^2 is y

square root of 4 is +2 as well as -2

so you would factorise it like this:

(y+2)(y-2)

1. y^4 has a square root of y^2 as y^2 × y^2 is y^4.

<em>h</em><em>o</em><em>w</em><em>e</em><em>v</em><em>e</em><em>r</em><em>,</em><em> </em>-2 doesnt have a whole number square root so it is not a difference of squares.

2. 25 has a square root of 5. m^2 has a square root of m. n^4 has a square root of n^2. so this 25m^2n^4 is a square term.

1 has a square root of +1 and -1.

therefore, this one is a difference of squares. <u>(</u><u>5</u><u>m</u><u>n</u><u>^</u><u>2</u><u> </u><u>+</u><u>1</u><u>)</u><u> </u><u>(</u><u>5</u><u>mn^2</u><u> </u><u>-</u><u>1</u><u>)</u>

3. p^8 has a square root of p^4. q^4 has a square root of +q^2 and -q^2)

so it is a difference of squares. <u>(</u><u>p</u><u>^</u><u>4</u><u>+</u><u>q</u><u>^</u><u>2</u><u>)</u><u>(</u><u>p</u><u>^</u><u>4</u><u> </u><u>-</u><u>q</u><u>^</u><u>2</u><u>)</u>

4. 16x^2 is a square term as irs square root is 4x.

<em>h</em><em>o</em><em>w</em><em>e</em><em>v</em><em>e</em><em>r</em><em>,</em><em> </em>24 is not a square term.

therefore, it is not a difference of squares.

6 0
3 years ago
Mr. sanchez recorded the number of visitors to a county park for 20 days and the average temperature for these 20 days. he recor
maria [59]
A, The temperature increase had increased the number of visitors.
4 0
3 years ago
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