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Doss [256]
3 years ago
14

Which ordered pairs make both inequalities true? Check all that apply.

Mathematics
2 answers:
Alex17521 [72]3 years ago
8 0

I JUST TOOK THE TEST AND THE ANSWER IS D

olga nikolaevna [1]3 years ago
3 0

Answer:

None of these ordered pairs make both inequalities true.

Step-by-step explanation:

The given inequalities are

y

y>x+1

For (-3,2),

2

The first inequality is not true for (-3,2), therefore option 1 is incorrect.

For (-1,3),

3

The first inequality is not true for (-1,3), therefore option 2 is incorrect.

For (0,2),

2

The first inequality is not true for (0,2), therefore option 3 is incorrect.

For (1,2),

2

2>1+1\Rightarrow 2>2

The second inequality is not true for (1,2), therefore option 4 is incorrect.

For (2,-1),

-1

-1>2+1\Rightarrow -1>3

The second inequality is not true for (2,-1), therefore option 5 is incorrect.

For (2,2),

2

2>2+1\Rightarrow 2>3

The second inequality is not true for (2,2), therefore option 6 is incorrect.

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Answer:

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Step-by-step explanation:

(3x^2+2x^2-5x+7)+(4x^2+2x-3)

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In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

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∴ 13 = \frac{1}{2} MO

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∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

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