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Ratling [72]
3 years ago
7

Select the correct answer.

Mathematics
1 answer:
marta [7]3 years ago
5 0
35.08 because all you have to do is 60.5 yards minus 25.42
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In a survey of 1,000 women aged 22 to 35 who work full time, 545 indicated that they would be willing to give up some personal t
sp2606 [1]

Answer:

Yes, there is convincing evidence that the majority of women age 22 to 35 who work full-time would be willing to give up some personal time for more money.

No ;

Step-by-step explanation:

n = 1000

x = 545

Phat = x / n = 545/1000 = 0.545

H0: p ≤ 0.5

H1: μ > 0.5

The test statistic :

(phat - p0) ÷ √(p(1 - P0) / n)

Test statistic :

(0.545 - 0.5) ÷ √(0.5(0.5) / 1000)

0.045 / 0.0158113

Test statistic = 2.846

α = 0.01

Decison :

Reject H0 ; if Pvalue < α

Using the Pvalue from Test statistic (Z) calculator :

Pvalue = 0.002214

With Pvalue < α ; We reject H0 and conclude that there is convincing evidence that the majority of women age 22 to 35 who work full-time would be willing to give up some personal time for more money.

No, making generalization about all women would not be reasonable as the data employed for the research mainly focuses on a particular

7 0
3 years ago
Solve the logarithmic equation: x= log5 (1/625)=
Verizon [17]
You can convert (1/625) to an exponent, and it would be ideal to have 5 as the base of it because you want your log base to cancel it out. what i usually do in this case is just test out 5^1, 5^2, etc until i find one that matches the number i need. in this case because the number you're trying to work with is a small fraction, you'll want to use NEGATIVE exponents so it'll create a fraction instead of a large whole number:

5^-1 = 1/5
. . . keep trying those. . .
5^-4 = 1/625

so, because they're equal to one another, it'll be waaay easier after you substitute 5^-4 in place of 1/625

x = log₅ 5⁻⁴

log base 5 of 5 simplifies to 1. subbing in the 5^-4 gets rid of the log for you altogether, and your -4 exponent drops down:

x = -4 is your answer

if the exponent dropping down doesn't make sense to you, you can think of it in another way:

x = log₅ 5⁻⁴

expand the expression so that the exponent moves in front of the log function:

x = (-4) log₅ 5

then, still, log base 5 of 5 simplifies to 1, so you're left with:

x = (-4)1 or x = -4
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=81%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20121%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" ti
scoundrel [369]
81.5 x 121.5= 9,902.25
8 0
3 years ago
How many 2.5" x 6" tiles with it on the backsplash that was 2.5 feet tall and 8 feet long
Dahasolnce [82]
24 cause you can only fit 24 on a backsplah

5 0
3 years ago
F(x) = { -2x -1, x ≤ 2
Degger [83]

Answer:

Use the appropriate entry method for piecewise functions for the graphing calculator of interest.

Step-by-step explanation:

For Desmos, the entry looks like ...

f(x) = {x ≤ 2: -2x-1,-x+4}

_____

For a TI-84 calculator, the entry may look like ...

Y₁ = (-2X–1)(X≤2) + (-X+4)(X>2)

The symbols ≤ and > come from the TEST menu, which is the (2nd) shift of the MATH key.

Note that the function is the sum of the pieces, each piece multiplied by a test. For something like 0≤x<2, the multiplier would be a pair of tests:

... (0≤X)(X<2)

8 0
3 years ago
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