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Ivenika [448]
3 years ago
10

Pls help me to answer this​

Mathematics
1 answer:
Fed [463]3 years ago
4 0

Answer:

i can't see the picture

Step-by-step explanation:

hmmmm what is ur question

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Answer the question in the picture pls WORTH 50 POINTS PLUS BRAINLIEST FOR FIRST CORRECT ANSWER
Alexus [3.1K]

Answer:

A

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

−y+4≥8

Step 2: Subtract 4 from both sides.

−y+4−4≥8−4

−y≥4

Step 3: Divide both sides by -1.

−y

−1

≥

4

−1

y≤−4

5 0
3 years ago
Read 2 more answers
Please help I'm on a test right now!!​
Svetach [21]
The answer would be 7-x.
8 0
3 years ago
Read 2 more answers
What value of n makes the equation true?
Naddik [55]

Answer:

n = 5.2.

Step-by-step explanation:

-20.8 = -4n

We divide both sides of the equation by -4:

-20.8 / -4 = -4n/-4

5.2 = n  (answer).

4 0
3 years ago
Read 2 more answers
Add and reduce to lowest terms: 5 1/4+4 5/6
lakkis [162]

Answer:

−6.7 + (−2 1/ 5 )

Step-by-step explanation:

−6.7 + (−2 1/ 5 )

4 0
3 years ago
Read 2 more answers
A manager is comparing wait times for customers in a coffee shop based on which employee is
anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

H_0: \mu_A - \mu_B = 0

At the alternative hypothesis, it is tested if there is difference, that is:

H_1: \mu_A - \mu_B = 0

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2

\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4

For the distribution of differences, we have that:

\overline{x} = \mu_A - \mu_B = 73 - 74 = -1

s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447

<h3>What is the test statistic?</h3>

It is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{-1 - 0}{0.447}

t = -2.24

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

8 0
2 years ago
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