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Olegator [25]
3 years ago
11

Determine whether the pair of equations is

Mathematics
1 answer:
ASHA 777 [7]3 years ago
8 0

Answer:

The answer is neither.

Step-by-step explanation:

We need to solve for y in the equation, 10x-2y= 6.

In other words, we are going to find the slope intercept of that equation.

10x - 2y = 6 \\  \frac{ + 10x =  + 10x}{ - 2y = 10x + 6}  \\  \\  \frac{ - 2y }{ - 2}  =  \frac{10x + 6}{ - 2}  \\ y =  - 5x  - 3

So we have now have both the equations:

y = 5x + 2 \\ and \\ y =  - 5x - 3

It's not parallel because the slopes aren't the same. It's not perpendicular because when the slope of the equation becomes a negative reciprocal, it still doesn't end up with the same slope as the other equation.

It's neither parallel or perpendicular.

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Joe purchased 15 pairs of socks from an online vendor and received a 20% discount. shipping cost $4.99. how much does each pair
cluponka [151]

Take the total: $79.99

Subtract the shipping cost: $4.99 ($75)

Divide that by the number of socks: 75/15
=$5 per sock with the discount

Take the discount of 20% and multiply that by the sock price $5 - 5 x .20 = 1

Add that to the sock price: 1 + 5 = 6

$6 per sock without the discount is your answer
7 0
3 years ago
4a+5b<br> When a=2 and b=(-3.1.)
Elan Coil [88]
4a+5b
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= -7.5
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3 years ago
PLEASE HELP ME ASAP!!<br><br> Answers:<br> undefined<br> Negative <br> Zero <br> Positive
Firdavs [7]
Positive since it’s rising :)
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3 years ago
Read 2 more answers
The point (–3, –5) is on the graph of a function. Which equation must be true regarding the function?
Artist 52 [7]

Answer:

f(-3)=-5

Step-by-step explanation:

we are given a point as

(-3,-5)

we know that any point can be represented as (x,y)

so, (x,y)=(-3,-5)

now, we can find x and y

we get

x=-3

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we know that any function can be represented as

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so, we can plug these values

and we get

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3 0
3 years ago
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Analytic function on unit disk with power series has pole on unit circle, then power series diverges on unit circle.
Wittaler [7]

Answer:

The function

{\ displaystyle f (z) = {\ frac {z} {1- | z | ^ {2}}}} {\ displaystyle f (z) = {\ frac {z} {1- | z | 2}

It is an example of real and bijective analytical function from the open drive disk to the Euclidean plane, its inverse is also an analytical function. Considered as a real two-dimensional analytical variety, the open drive disk is therefore isomorphic to the complete plane. In particular, the open drive disk is homeomorphic to the complete plan.

However, there is no bijective compliant application between the drive disk and the plane. Considered as the Riemann surface, the drive disk is therefore different from the complex plane.

There are bijective conforming applications between the open disk drive and the upper semiplane and therefore determined as Riemann surfaces, are isomorphic (in fact "biholomorphic" or "conformingly equivalent"). Much more in general, Riemann's theorem on applications states that the entire open set and simply connection of the complex plane that is different from the whole complex plane admits a bijective compliant application with the open drive disk. A bijective compliant application between the drive disk and the upper half plane is the Möbius transformation:

{\ displaystyle g (z) = i {\ frac {1 + z} {1-z}}} {\ displaystyle g (z) = i {\ frac {1 + z} {1-z}}}

which is the inverse of the transformation of Cayley.

8 0
4 years ago
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