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Answer:
2102.13 mm^2
Attached is a completed image of the question
Step-by-step explanation:
Given;
Radius of the circle r = KL = 27.1 mm
Angle of unshaded region = 32°
The total angle in a circle is 360°
Angle of shaded region θ = 360° - angle of unshaded region.
θ = 360° - 32° = 328°
The Area of a circle = πr^2
Area of shaded region A = (θ/360)πr^2
Substituting the given values;
A = (328/360)×π × 27.1^2
Area of shaded region A = 2102.13 mm^2
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
Using Heron's Formula we can find the area of the triangle.
A = root (s (s-a) * (s-b) * (s-c))
s = (a + b + c) / 2
Where,
s: semi-perimeter
a, b, c: sides of the triangle
Substituting values:
s = (15 + 16 + 20) / 2
s = 25.5
s = 26
The area will be:
A = root (26 * (26-15) * (26-16) * (26-20))
A = 130.9961832
A = 130 u ^ 2
Answer:
The area of triangle ABC is:
C.
130 u ^ 2
SEE ATTACHED IMAGE.
Using Heron's Formula we can find the area of the triangle.
A = root (s (s-a) * (s-b) * (s-c))
s = (a + b + c) / 2
Where,
s: semi-perimeter
a, b, c: sides of the triangle
Substituting values:
s = (15 + 16 + 20) / 2
s = 25.5
s = 26
The area will be:
A = root (26 * (26-15) * (26-16) * (26-20))
A = 130.9961832
A = 130 u ^ 2
Answer:
The area of triangle ABC is:
C.
130 u ^ 2