What is the solution to this system of equations? On a coordinate plane, 2 lines intersect at (negative 6, negative 2). What is
2 answers:
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Hello,
A=(-4,2)
B=(3,-5)
AB≡y-2=(x+4)(-7)/7==>y=-x-2
Slope of the perpendicular: 1
y-2=(x-1)1==>y=x+1 is the equation of the perpendicular.
Intersection: y=x+1 and y=-x-2 ==>(-3/2,-1/2)=Q
|PQ|²=(-1/2-2)²+(1+3/2)²=25/2
|PQ|=5√2/2≈3.5355339059....
A=(-4,2)
B=(3,-5)
AB≡y-2=(x+4)(-7)/7==>y=-x-2
Slope of the perpendicular: 1
y-2=(x-1)1==>y=x+1 is the equation of the perpendicular.
Intersection: y=x+1 and y=-x-2 ==>(-3/2,-1/2)=Q
|PQ|²=(-1/2-2)²+(1+3/2)²=25/2
|PQ|=5√2/2≈3.5355339059....