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Zarrin [17]
2 years ago
9

Solve the equation for x. 15 + 2x = 5 + 3x O No solution 05 0 10

Mathematics
2 answers:
Lina20 [59]2 years ago
8 0

Answer:

x=10

Step-by-step explanation:

15+2x=5+3x

15=5+x

10=x

Oksana_A [137]2 years ago
7 0
X= 10 siehehhehehejedjd
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red cuz its an odd number so every even number row is blue

Step-by-step explanation:

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2 years ago
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Quadrilateral ABCD ​ is inscribed in this circle.
Lelechka [254]

Answer:

m∠C = 122°

Step-by-step explanation:

Opposite angles of a quadrilateral inscribed in a circle are supplementary. This means

m∠A + m∠C = 180°

m∠B + m∠D = 180°

To find angle C we need to find x, then subtract m∠A from 180°

x+20=3x

20=2x

x=10

Now we substitute 10 in for x

m∠A=2(10)+38

m∠A=20+38

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4 0
2 years ago
K + 4(5k +6) = - 123 <br> HELP ASAP
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Answer:

-7

Step-by-step explanation:

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4 0
2 years ago
Consider the function f(x)=−3/4 x+1.
jenyasd209 [6]
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7 0
2 years ago
Perform the indicated operation to write given polynomial in standard form: (x^3+2x^2 − 3x − 1) +(4 − x − x^3)
Rzqust [24]

Answer:

\left(x^3+2x^2-3x-1\right)+\left(4-x-x^3\right)=2x^2-4x+3

Step-by-step explanation:

To write any polynomial in standard form, you look at the degree of each term. You then write each term in order of degree, from highest to lowest, left to write.

To add the polynomials you need to:

Remove parentheses

\left(x^3+2x^2-3x-1\right)+\left(4-x-x^3\right)=x^3+2x^2-3x-1+4-x-x^3

Group like terms

\left(x^3+2x^2-3x-1\right)+\left(4-x-x^3\right)=x^3-x^3+2x^2-3x-x-1+4

Add similar elements

\left(x^3+2x^2-3x-1\right)+\left(4-x-x^3\right)=2x^2-3x-x-1+4\\\left(x^3+2x^2-3x-1\right)+\left(4-x-x^3\right)=2x^2-4x-1+4\\\left(x^3+2x^2-3x-1\right)+\left(4-x-x^3\right)=2x^2-4x+3

5 0
3 years ago
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