Given Information:
Mean SAT score = μ = 1500
Standard deviation of SAT score = σ = 3
00
Required Information:
Minimum score in the top 10% of this test that qualifies for the scholarship = ?
Answer:

Step-by-step explanation:
What is Normal Distribution?
We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.
We want to find out the minimum score that qualifies for the scholarship by scoring in the top 10% of this test.

The z-score corresponding to the probability of 0.90 is 1.28 (from the z-table)

Therefore, you need to score 1884 in order to qualify for the scholarship.
How to use z-table?
Step 1:
In the z-table, find the probability value of 0.90 and note down the value of the that row which is 1.2
Step 2:
Then look up at the top of z-table and note down the value of the that column which is 0.08
Step 3:
Finally, note down the intersection of step 1 and step 2 which is 1.28
Well, 10x4=40 because 10+10+10+10=40 and that means your answer must be 40 ones or you asked something else.
here 8x and (2x+60) are corresponding angles
since line l1 and l2 are parallel, so the two angles will be equal
8x=2x+60
8x-2x=60
6x=60
dividing by 6
x=10
option D. 10 is correct
<span>46, 37, 16, 24, 47, 23, 19, 31, 25
put in order</span>
16, 19, 23, 24, 25, 31,37, 46, 47
mean = 25
LOWER QUARTILE = (16+ 19+ 23+ 24) / 4 = 20.5
answer
Lower IQR = 20.5
Answer:
Marta need to score at least 94 to receive an average of 90 or higher considering all five tests.
Explanation:
Marks received by Marta in four tests = 86, 84, 97 and 89
Let mark received in fifth test be x
We have average of five test is more than or equal to 90
So we have

So Marta need to score at least 94 to receive an average of 90 or higher considering all five tests.