Answer: P(22 ≤ x ≤ 29) = 0.703
Step-by-step explanation:
Since the machine's output is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = output of the machine in ounces per cup.
µ = mean output
σ = standard deviation
From the information given,
µ = 27
σ = 3
The probability of filling a cup between 22 and 29 ounces is expressed as
P(22 ≤ x ≤ 29)
For x = 22,
z = (22 - 27)/3 = - 1.67
Looking at the normal distribution table, the probability corresponding to the z score is 0.047
For x = 29,
z = (29 - 27)/3 = 0.67
Looking at the normal distribution table, the probability corresponding to the z score is 0.75
Therefore,
P(22 ≤ x ≤ 29) = 0.75 - 0.047 = 0.703
The graph that has a slop of -1 and the y-interecept is 4
that graph is the 1st picture and top one
Step-by-step explanation:
from,
An = 4n -13
A1 = 4 (1) - 13
> A1 = -9
A2 = 4(2) - 13
> A2 = -5
A3 = 4(3) - 13
> A3 = -1
A4 = 4(4) - 13
> A4 = 3
The second side of a triangular deck is 4 feet longer than the shortest side
(s+4) = the 2nd side
and a third side that is 4 feet shorter than twice the length of the shortest side.
(2s-4) = the 3rd side
If the perimeter of the deck is 48 feet, what are the lengths of the three sides?
s + (s+4) + (2s-4) = 48
Combine like terms
s + s + 2s + 4 - 4 = 48
4s = 48
s = 48/4
s = 12 ft is the shortest side
I'll let you find the 2nd and 3rd sides, ensure they add up to 48
Hope this helps!
Answer:
The correct option is B
Step-by-step explanation:
From the question we are told that
The sample size is 
The proportion that choose to vaccinate the teen boys is 
considering the first statement
The 95% confidence interval is 12% ± the margin of error*standard deviation is false because
The 95% confidence interval is is %12 ± the margin of error
considering the second statement
The confidence interval should not be calculated due to the small sample size is true because from the central limit theorem
np = 64 * 0.12 = 7.68
and this value is less than 10 hence the confidence interval should not be calculated
considering the third statement
A 99% confidence interval will be smaller than the 90% confidence interval is false
This is because as the confidence level increase (for example from 90% to 99%) the margin of error increase which increases the confidence interval